3 years ago

The square root of 8 to the 3rd power

Mathematics

1 answer:

zlopas [31]3 years ago

7 0

It’s might b 24 hopefully this helps u

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The diagram shows triangle ABC.

const2013 [10]

Answer:

Step-by-step explanation:

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2 years ago

WILL MARK BRAINLIEST!! PLZ HELP!!! 20 POINTS Create a graph of the polynomial function g(x) = (x + 2)(x − 1)(x − 2)

Gennadij [26K]

Answer:

We have: g(x)=(x+2)(x-1)(x-2)

multiply the 3 terms:

(x+2)(x-1)(x-2)
(x²-4)(x-1)
x^3 -x²-4x+4

This is a polynimial function with 2 vertices

The roots are approximatively:

0.8 and -1.5

their images are:

1.9 and 8.8

plot these two vertices and draw some other points

here is a drawing:

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3 years ago

What is 1 38/40 simplified

sesenic [268]

Your answer will be 1 19/20

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3 years ago

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I need help the question is on the picture

Genrish500 [490]

Answer:

Blank 1: 12.5 mph

Blank 2: .36 hours

Step-by-step explanation:

1. 3.75/.3 = 12.5

2. 4.5/12.5 = .36

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3 years ago

Find an explicit solution to the Bernoulli equation. y'-1/3 y = 1/3 xe^xln(x)y^-2

NNADVOKAT [17]

$y'-\dfrac13y=\dfrac13xe^x\ln x\,y^{-2}$

Divide both sides by $\dfrac13y^{-2}(x)$ :

$3y^2y'-y^3=xe^x\ln x$

Substitute $v(x)=y(x)^3$ , so that $v'(x)=3y(x)^2y'(x)$ .

$v'-v=xe^x\ln x$

Multiply both sides by $e^{-x}$ :

$e^{-x}v'-e^{-x}v=x\ln x$

The left side can be condensed into the derivative of a product.

$(e^{-x}v)'=x\ln x$

Integrate both sides to get

$e^{-x}v=\dfrac12x^2\ln x-\dfrac14x^2+C$

Solve for $v(x)$ :

$v=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

Solve for $y(x)$ :

$y^3=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

$\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}$

4 0

3 years ago