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Ugo [173]
2 years ago
13

Expand the following numbers 349056​

Mathematics
1 answer:
zimovet [89]2 years ago
8 0

Answer:

easyy

Step-by-step explanation:

It's B

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Find the difference: 101100012 - 11011012. Express your answer as a Base<br> 2 number.
Marizza181 [45]

Answer:

<h2>The answer is 1000100</h2>

Step-by-step explanation:

10110001 - 1101101 = 1000100

Hope this helps you

7 0
2 years ago
The diagram shows a right-angled triangle.
Karo-lina-s [1.5K]

Answer:

sorry j don't have my calculator but

sine of angle x°=opposite 6cm/9cm

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2 years ago
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True or False? The graph of sine can be used to construct the graph of the secant function.
amid [387]

True

Note that:

secant \theta = \frac{1}{cos\theta}

The graph of sine and cosine functions are very similar. They only have a shift in the x -axis.

That is,  sin x  =  cos (90  -  x)

Since there is a great similarity between the sine and cosine graphs, and the secant graph is an inverse of the cosine graph, the graph of sine can be used to construct the graph of the secant function

Mathematically:

since  sec x  =  1 / cos x

and, cos x = sin (90 - x)

therefore, sec x = 1 / sin (90 - x)

The graphs of the sine and secant functions are attached to this solution

Learn more here: brainly.com/question/9554579

5 0
3 years ago
What is the vertex? <br> What is the domain? <br> What is the range
kati45 [8]

domain-x intercept

range-y intercept

3 0
2 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
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