10,000,000+2,000,000+400,000+30,000+0+0+0
Answer: 72
Step-by-step explanation:
(8-(2-2))×9
First do (2-2=0)
(8-0=8)
8×9=72
Hope this helps
Answer: 0.0668073
Step-by-step explanation:
Given : The number of miles each tire lasts before it completely wares out follows a normal distribution with mean μ = 50,000 miles and standard deviation σ = 8,000 miles.
Let x be the random variable that represents the number of miles each tire lasts.
z-score : 
For x= 62,000

By using the standard z-value table , the probability for a randomly selected tire to last for at least 62,000 miles will be :_

Hence, the probability for a randomly selected tire to last for at least 62,000 miles = 0.0668073
Answer:
1
Step-by-step explanation:
GCF(18, a, 20ab) = 1
18 and <em>a</em> do not necessarily have any factor in common, so their GCF is 1. Adding more terms to the list will not increase the GCF beyond that value.