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3 years ago

The line of best fit was drawn and the equation for the height (h) and weight (w) was determined to be

Mathematics

1 answer:

pishuonlain [190]3 years ago

4 0

Answer:due to t following ten advantag- e 1 Weighs to 250 gran: chout weights V rate "to A of a gran, ..

Step-by-step explanation:

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Mrs. Kelso and Mr. Bonham gave each their student a small bag of colored tiles. The student each counted the number of purple ti

skelet666 [1.2K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Is the point 3/5 and 4/5 corresponds to an angle in the unit circle what is the csc

Mariulka [41]

<u>Answer:</u>

csc = 5/4

<u>Step-by-step explanation:</u>

Assuming that the two given points 3/5 and 4/5 are the two sides of a triangle and a right angle 0 with legs x and y and z as its hypotenuse.

Then using Pythagoras Theorem:

$z^2=x^2+y^2$

$z^2=(\frac{3}{5} )^2+(\frac{4}{5} )^2$

$z^2 = \frac{9}{25} + \frac{16}{25}$

$z^2=\frac{25}{25}$

$z^2=1$

Taking square root on both the sides:

$z=1$

Now, $sin\alpha=\frac{4}{5}$

and we know that $csc = \frac{1}{sin\alpha }$

Therefore, csc = 5/4.

8 0

4 years ago

Find the determinant of the following matrix. [1 -2] [3 4]

Andrew [12]

Answer:

Step-by-step explanation:

[1 -2]

[3 4]

We can obtain the determinant of the above matrix by doing the following:

Determinant =(1 × 4) – (3 × –2)

Determinant = 4 – – 6

Determinant = 4 + 6

Determinant = 10

Thus, the determinant of the above matrix is 10

8 0

3 years ago

Assume that we have m coins. We toss each one of them n times. The probability of heads showing up for each coin isp. What’s the

olga nikolaevna [1]

Answer:

$1-(1-p^n)^m$

Step-by-step explanation:

For a coin, the probability of head showing in a single toss is $p$ .

$P(H)=p$

Its complement, the probability of not head is

$P(\Sim H)=1-p$

This is a binomial distribution. In $n$ tosses, the probability of having all heads (i.e. $n$ heads) is

$P(\text{all heads})=\binom{n}{n}p^n(1-p)^0=p^n$

Let's call this value $a$ .

For $m$ coins, we determine the probability of at least 1 coin showing all heads by first finding its complement i.e. the probability of no coin showing all heads. This is also a binomial distribution.

$P(\text{no coin showing all heads})=\binom{m}{0}a^0(1-a)^m=(1-a)^m$

$P(\text{at least 1 coin showing all heads})=1-P(\text{no coin showing all heads})$

$P(\text{no coin showing all heads})=1-(1-a)^m=1-(1-p^n)^m$

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3 years ago

a box contains 5 chocolate chip cookies, 4 sugar and 6 oatmeal raisin. what is the probability of picking a chocolate chip cooki

LenaWriter [7]

Answer:

5 out of 15

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers