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storchak [24]
1 year ago
13

To find the factors of a polynomial from its graph, follow this rule: if the number ___ is a root of a polynomial, then x-c is a

factor. (FILL IN THE WORD QUESTION)

Mathematics
1 answer:
egoroff_w [7]1 year ago
8 0

Solution

if the number _C__ is a root of a polynomial, then x-c is a factor.

Whenever we have a polynomial

Example

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2. Ms. Groves has trays of paints for students in her
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Answer:

Each tray has 5 colours and one of the colour on the tray is purple. Hence 1/5 of the colours on the tray is purple and thus 1/5 of the colours on the 20 trays is purple. The fraction of colours on the trays will not change. If written out logically, 20 purples out of 100 colours in total on the trays will also given the fraction 1/5.

4 0
3 years ago
The table below shows the linear relationship between the number of people at a picnic and the total cost of the picnic which st
sesenic [268]

Answer

The independent variable is the number of people. The initial value (initial fee) for the picnic is $40. As the number of people increases, the total cost of the picnic increases.

8 0
3 years ago
I WILL GIVE BRAINLIEST
Andre45 [30]

Hello there! Your answer is B. Negative.

Since -4 and -3/4 are both negatives, the negatives cancel eachother out and you are left with a positive. :)

7 0
3 years ago
A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points ex
Serga [27]
<h3>Answer:  127</h3>

=================================================

Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

  • first exam = 70
  • second exam = 80
  • third exam = 43
  • fourth exam = x+5

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

(x+198)/4 = 80

x+198 = 4*80

x+198 = 320

x = 320 - 198

x = 122

So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

7 0
3 years ago
In ΔABC shown below, BD over BA equals BE over BC:
lbvjy [14]
Pls. see attachment. 

5 0
3 years ago
Read 2 more answers
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