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worty [1.4K]
3 years ago
14

Given f (x) = 2x+3 and g(x) = 4x + 3, find each of the following. b. f(4) = a. g(-2)=

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

Step-by-step explanation:

dn3edhb3rbrjfnfjbhghrbhjbrhhb fh3hfnhbjnjhbjffjhnj3 njn

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How many blocks with dimensions of One-third times 1 times 1 can fit in a unit cube?
gtnhenbr [62]

Answer: 3

Step-by-step explanation:

Given

The dimension of the small block is

\dfrac{1}{3}\times 1\times 1

The Volume of the cube having unit length is

V=1\times 1\times 1\\V=1\ unit^3

The number of blocks that can be in the unit cube is the division of the volume of the unit cube and block.

\Rightarrow \dfrac{1\times 1\times 1}{\dfrac{1}{3}\times 1\times 1}\\\\\Rightarrow \dfrac{3}{1}=3

7 0
3 years ago
Read 2 more answers
What is the example of 897 * 39+(34*964)
Verizon [17]

Answer:

a_n=a_1+(n-1)d

Step-by-step explanation:

sorry for late anwser

4 0
3 years ago
What is the solución of the equation x2-4x+1=0?
koban [17]

Answer:

x = 2 + √3 and

x = 2 - √3

Step-by-step explanation:

Please use " ^ " to denote exponentiation:  x^2 - 4x + 1 = 0.

Here you have multiple choices of methods of solution:

quadratic formula, completing the square, graphing, and so on.

If we complete the square, then:                   x^2 - 4x + 1 = 0 becomes

                                                                       x^2 - 4x + 4 - 4 + 1 = 0, or

(x - 2)^2 = 3

Taking the square root of both sides, we get x - 2 = ±√3, so that the roots are:

x = 2 + √3 and

x = 2 - √3

6 0
4 years ago
The diameter of a circle is 28 inches what is the circle's area?<br><br> use 3.14 for pi
jolli1 [7]

Answer:

615.75216....

Step-by-step explanation:

The formula is A = π * (ø/ 2)^2

A = Circle area

π = Pi = 3.14

ø = Circle diameter

A= 3.14  (28/2)^2

5 0
3 years ago
Read 2 more answers
The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the
aleksandrvk [35]
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =

(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =

= 2a^3 - 2(a^3)/3 = [4/3](a^3)

Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3

ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
 



3 0
3 years ago
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