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Temka [501]
3 years ago
12

Help me PLEASEEEEEEEEEEEE :C

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
7 0

Answer:

C. Negative correlation

Step-by-step explanation:

I hope this is correct,

Have a nice day!!

Natalija [7]3 years ago
4 0

Answer:

im thinking number #A but it also d

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Add then divide.<br> Evaluate<br> (7.3 X 10) + (2.4 X 107)<br> (4 X 104)
Deffense [45]

Answer:

6.0 x 10^2

Step-by-step explanation:

(7.3 X 10) + (2.4 X 10^7)

(4 X 10^4)

= 73 + 24000000

40000

= 24000073

40000

= 6.0 x 10^2

4 0
2 years ago
If you put $603 in a savings account that pays 9% for one year what is the amount of money you will have at the end of the one y
Juliette [100K]

603*.09=54.27 so add 603+54.27= 657.27

5 0
3 years ago
(4 + y = 19) what is y
Fiesta28 [93]
4 + y = 19

y = 19 - 4

y = 15
5 0
3 years ago
On the grid, sketch a graph to represent
Greeley [361]

Answer:

Please find attached, the required graph created on MS Excel

Step-by-step explanation:

The distance between Sandy's house and the school = 200 m

The number of minutes Sandy talked to her friend for = 10 minutes

The time it took Sandy to return home to pick her homework = 5 minutes

Let <em>x </em>represent Sandy's location she stops to talk to her friend 10 minutes, we have;

The slope of the motion on the graph, m₁ = (x - 0)/(t - 0)

The slope of her motion running home to pick the up her homework, m₂ = (x - 0)/(5 - 0)

Given that t > 5, the slope on trip back home, m₁, is larger than are her initial slope, m₂

Therefore, where x = 125, we have;

The rate at which she returned home = m₂ = (125 m - 0)/(5 min - 0) = 25 m/min

Given that the same rate m₂ is what she used in heading back to school, we have;

The time it takes her to get to school = 200 m/(25 m/min) = 8 minutes

Therefore, whereby it took her 10 minutes to reach point <em>x</em>, we have the following coordinate points on the graph in a tabular form;

\begin{array}{ccc} Time \ (minutes) \ x-axis&&Distance  \ (meters) \ y-axis\\0&&0\\10&&25\\15&&0\\23&&200\end{array}

The plot of the above point is completed using MS Excel as shown in the attached diagram.

7 0
2 years ago
Jordan buys a car for £5000. It depreciates buy 23% per year. How much is it worth after 5 years?
Basile [38]
The answer can be computed as follows:
                                   worth = £5000(1 - 0.23)^(5) = <span>£1353.39
It is approximately worth </span><span>£1353.39 after 5 years.</span>
3 0
3 years ago
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