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Nookie1986 [14]
3 years ago
6

The capacity of a beamer is 0.1 liter. convert this to milliliters

Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

A milliliter is a thousandth of a liter. 1,000 milliliters (mL) are in a liter. So, multiply 0.1 by a thousand to find the answer. The answer is 100.

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Some1 hurry up plzzz need help
Step2247 [10]

Answer:

IM pretty sure b) and c)

Step-by-step explanation:

3 0
2 years ago
4/5 divided by 3 fraction.......​
astra-53 [7]

Answer:

4/15

Step-by-step explanation:

\frac{\frac{4}{5} }{3}=\frac{4}{5}(\frac{1}{3})=\frac{4}{15}

5 0
3 years ago
Given the equation 4x2 − 8x 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 k = 0?
Westkost [7]

The vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

According to the given question.

We have a quadratic equation

4x^{2} -8x + 20 = 0

Since, for the standard quadratic form is ax^{2} +bx + c = y, the vertex form of a quadratic equation is y = a(x -h)^{2} + k where (h, k) is the vertex.    

And h and k can be calculated as

h = -b/2a and y = k

So, for the given equation 4x^{2} -8x + 20 =0 the vertex (h, k) is given by

h = -(-8)/2(4) = 8/8 = 1   (X coordinate of vertex)

and,

y =4x^{2} -8x+ 20

substitute x = 1 in the above equation for the value of k

Y = 4(1)(1) - 8(1) + 20

⇒ Y = 4 - 8 + 20

⇒ Y = -4 + 20

⇒ Y = 16

so, k = 16          (Y coordinate of vertex)

Now, substitute the value of a, k and h in y = a(x-h)^{2} + k.

⇒  0 =4(x-1)^{2} + 16

Therefore, the vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

Find out more information about vertex form of a quadratic equation here:

brainly.com/question/12223454

#SPJ4

6 0
1 year ago
Is y=2x+4 non-proprtonal or propportional
natali 33 [55]

Answer:

non-proprtonal

Step-by-step explanation:

8 0
3 years ago
Can somebody help me to factorice this?
OverLord2011 [107]

Answer:

(r^2 - r - 1)(r^2 + r - 1).

Step-by-step explanation:

r^4 - 3r^2 + 1

We need to make this into  a perfect square so the r^4 and the  1  fit the bill but not the  -3r^2 so we have to correct for that.

A perfect square would be:

r^4 - 2r^2 + 1       ( = (r^2 - 1)^2 )

But we need -3r^2  so we add - r^2 at the end:

= (r^4 - 2r^2 + 1)  - r^2   So now we have the difference of 2 squares and we write:

(r^2 - 1)^2 - r^2

= (r^2 - 1 - r)(r^2 - 1 + r)

= (r^2 - r - 1)(r^2 + r - 1)

8 0
2 years ago
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