Answer:
1.-12*(2r)^11 * (3s)
= -12*2048*3 r^11 s
= -73728 r^11 s
2.12C1 (2r)¹¹(-3s) = -36(2¹¹)r¹¹s = -73728r¹¹s
3.24 r - 36 s
The second term: -36 s
4.(2r-3s)^12
= (2r)^12 + 12C1 (2r)^11 (-3s)
= 2^12 r^12 + (12) 2^11 r^11 (-3) s
= 4096 r^12 - (12)(3)(2098) r^11 s
= 4096 r^12 - 73,728 r^11 s + .....
-73,728 r^11 s
Step-by-step explanation:
Yan lang po alam ko at nahirapan ako e solved yan hehe pero hope it helps
Answer:
Step-by-step explanation:
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Make note of the coefficients in the first and fourth equations. They've been conveniently picked so that subtracting one equation from the other eliminates every variable but <em>t</em>. We have
(3<em>r</em> + 2<em>s</em> + <em>t</em> + 2<em>u</em> + 3<em>v</em>) - (3<em>r</em> + 2<em>s</em> + 3<em>t</em> + 2<em>u</em> + 3<em>v</em>) = 7 - 17
-2<em>t</em> = -10
<em>t</em> = 5
9514 1404 393
Answer:
h ≤ 6 2/3
Step-by-step explanation:
The inequality is presumed to be ...
15h +40 ≤ 140
15h ≤ 100
h ≤ 6 2/3
__
The graph shows h ≥ 0, because the inequality is only reasonable for h ≥ 0.
Answer:
3 and 1
Step-by-step explanation:
the sequence is dividing each # by 2
