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Kruka [31]
3 years ago
12

What is the answer for 64-6x+4

Mathematics
1 answer:
Crank3 years ago
6 0
Are you solving for x? If not the answer is 21.14893616
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In IJK, the measure of K=90°, KI = 8.1 feet, and JK = 1.9 feet. Find the measure of
Alborosie

Answer:

77

Step-by-step explanation:

8 0
3 years ago
Step 3: Calculating time
klasskru [66]

Part A

See the diagram below for the table.

Here's how to set up the table.

Let t be the time it takes to make the return trip.

15 min = (15 min)*(1 hr/60min)

15 min = (15/60) hr

15 min = 1/4 hr

Since the cheetah traveled 15 minutes total, this means it traveled 1/4 of an hour total.

If it took t hours to go back home then it took 1/4 - t hours to get to the river. The values in the time column must add up to 1/4 hour.

The speeds given to us are placed in the table as is.

Multiply those speeds with the time expressions to get the distance expressions.

For the first distance we get

d = r*t

d = 40*(1/4-t)

d = 40*(1/4)+40*(-t)

d = 10-40t

Representing the distance traveled going from home to the river.

The second distance equation is

d = r*t

d = 70*t

==========================================================

Part B

The equation is 10-40t  = 70t

Simply set each distance equal to one another. This works because the cheetah travels the same distance from home to the river, and then back again.

In other words,

distance from home to river = distance from river to home

==========================================================

Part C

Let's solve the equation formed in part B

10-40t = 70t

10-40t+40t = 70t+40t .... adding 40t to both sides

10 = 110t

110t = 10

110t/110 = 10/110 .... dividing both sides by 110

t = 1/11 hours

t = 60/11 minutes .... multiply by 60 to convert from hrs to min

t = 3600/11 seconds ... multiply by 60 to convert from min to sec

So,

3600/11 sec = 327.2727 sec

3600/11 sec = (300 sec) + (27.2727 sec)

3600/11 sec = (300/60) min + (27.2727 sec)

3600/11 sec = 5 min + 27.2727 sec

3600/11 sec = 5 min,  27.2727 sec

Answer: Approximately 5 min,  27.2727 sec

5 0
3 years ago
Craig left his house at noon and drove 50 miles per hour until 3PM. Then he drove the next 5 hours at 70 miles per hour. Calcula
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Craig left his house at noon and drove 50 miles per hour until 3PM. Then he drove the next 5 hours at 70 miles per hour. Calculate the average rate of change for the entire trip.

7 0
3 years ago
Find an equation of a parabola with a vertex at the origin and directrix X = 2.5
adell [148]
Vertex=(0,0)
directrix is x=2.5
or x-2.5=0
so focus  S is (-2.5,0)
let P(x,y)be any point on the parabola.
Let M be the foot of perpendicular from P(x,y) on the directrix.
then SP=PM
\sqrt{(x-(-2.5))^2+(y-0)^2} =| \frac{x-2.5}{( \sqrt{1})^2 } |
squaring both sides(x+2.5)^2+y^2=(x-2.5)^2 , x^2+6.25+5x+y^2=x^2+6.25-5x

y^2=x^2+6.25-5x-x^2-6.25-5x=-10x
so eq. is  y^{2} =-10x


7 0
4 years ago
How can I solve (-12 =2 + k)
ZanzabumX [31]
You would want to go by reverse order of operations. This is a one step equation. You subtract 2 on both sides, in which you will get: -14 = k.
3 0
3 years ago
Read 2 more answers
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