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3 years ago

What is the answer for 64-6x+4

Mathematics

1 answer:

Crank3 years ago

6 0

Are you solving for x? If not the answer is 21.14893616

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Factor completely, then place the answer in the proper location on the grid. <br> 6х^2 - 3х - 30

Tems11 [23]

Answer:

3(x + 2)(2x - 5)

Step-by-step explanation:

Given

6x² - 3x - 30 ← factor out 3 from each term

= 3(2x² - x - 10) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 10 = - 20 and sum = - 1

The factors are + 4 and - 5

Use these factors to split the x- term

2x² + 4x - 5x - 10 ( factor the first/second and third/fourth terms )

= 2x(x + 2) - 5(x + 2) ← factor out (x + 2) from each term

= (x + 2)(2x - 5), thus

2x² - x - 10 = (x + 2)(2x - 5) and

6x² - 3x - 30

= 3(x + 2)(2x - 5) ← in factored form

7 0

4 years ago

You are remodeling your bedroom. You will paint all 4 walls and the door. There are 2 windows in the room. The windows both meas

Bogdan [553]

Answer: it’s easy look it up on a calculator

Step-by-step explanation:

6 0

3 years ago

Jerry had $740 in the savings account at 5% interest the money is in the account for 1/4 year how much interest did he receive?s

Darya [45]

He will withdraw $856.64

8 0

4 years ago

5x-7<7x-11<5x+9 <br> Give your answer in interval notation

skelet666 [1.2K]

Answer:

In pic below

Step-by-step explanation:

4 0

3 years ago

The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2

Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in $^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15$ ways.

The probability of getting two 3 as outcome is $\frac{1}{4} \times\frac{1}{4} = \frac{1}{16}$ .

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is $1 - \frac{1}{4} = \frac{3}{4}$ .

Hence, the required probability is $15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}$ ≅0.2966 or, 0.23.

4 0

3 years ago