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Naily [24]
3 years ago
5

Five and fifty-six thousandths in decimal form

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0

Answer:

5.056

Step-by-step explanation:

The 5 is in the one's place and the 56 is in the thousandths place, so there's nothing in the tenths.

Lerok [7]3 years ago
3 0

Answer:

0.056

Step-by-step explanation:

:) hope this helps

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Write the expansion of each binomial. (x-y)^4
TEA [102]
When you expand the binomial, you isolate each of the parts.
So, (x-y)^4 would turn into...

x^4 - y^4

The powers stay the same because (outside the parenthesis) you multiply them with whatever is inside the parenthesis. In this case, would be 1. All variables and numbers without a listed power have a power of one. Multiply 4*1 to get 4. 
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3 years ago
Serena is making an experiment. For that, she needs 20 grams of a 52% solution of salt. She has two large bottles of salt water:
Fudgin [204]
X + y = 20 --> eqn 1
The second equation would be the mass balance shown below:
(x)(0.40) + y(0.70) = 20(0.52) --> eqn 2
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Therefore, Serena needs 12 grams of the 40% solution and 8 grams of the 70% solution.
 
5 0
4 years ago
Please help with number 8
Oxana [17]

Answer:

64

Step-by-step explanation:

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4 0
3 years ago
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liraira [26]
40 is the correct answer. Hope this helps :)
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Anna007 [38]

h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

\boxed{h(x) =  \frac{2 {x}^{2}  - x + 1}{3x - 2}}

h(2) =  \frac{2 {(2)}^{2}  - (2) + 1}{3(2) - 2}

h(2) =  \frac{2 {(4)}  - 2 + 1}{6 - 2}

h(2) =  \frac{ 8  - 1}{4}

h(2) =  \frac{7}{4}

h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

h( - 2) =  \frac{2 {( - 2)}^{2}  - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) =  \frac{2 (4)  +  2+ 1}{- 6 - 2} \\ h( - 2) =  \frac{8 +  3}{- 8} \\ h( - 2) =  \frac{11}{- 8}

h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}

5 0
3 years ago
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