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mylen [45]
3 years ago
14

What are the number of people who attended a rally?

Mathematics
2 answers:
ANTONII [103]3 years ago
5 0

Answer:

hope to help

Step-by-step explanation:

carryonlearning

Pie3 years ago
5 0

100,000-65,245=34,755

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Find the radius and center of the circle given by the equation below. (x – 6)2 + (y + 4)2 = 7 r = 7 and center at (-6, 4) r = 7
Blababa [14]

Answer:

center at (6, -4) r = √7

Step-by-step explanation:

(x – 6)^2 + (y + 4)^2 = 7

This is in the form

(x – h)^2 + (y - k)^2 = r^2

Where (h,k) is the center of the circle and r is the radius of the circle

Rearranging the equation to match this form

(x – 6)^2 + (y -- 4)^2 = sqrt(7) ^2

The center is at (6, -4) and the radius is the sqrt(7)

3 0
3 years ago
Please Simplify the equation (-6) ^-2
xeze [42]

Answer:

1/36

Step-by-step explanation:

(-6) ^-2

The negative in the exponent means in goes from the numerator to the denominator

(-6) ^-2 = 1/ (-6)^2

We know that

(-6)^2 = -6*-6 = 36

(-6) ^-2 = 1/ 36

5 0
3 years ago
Read 2 more answers
What is the volume of a block with dimensions 2.56cm x 4.652 cm x 8.70 cm ??
mihalych1998 [28]
2.56 x 4.652 x 8.70 = <span>103.61 milliliters</span>
4 0
4 years ago
In a school of 3200 total students 3/8
dmitriy555 [2]

Answer:

i) Boys:1200; Girls:2000

Boys:37.5%; Girls:62.5%

Step-by-step explanation:

i) Boys: 3200*(3/8) =1200

Girls: 3200-1200 =2000

ii) Boys: (1200/3200)*100%= 37.5%

Girls: 100%- 37.5%= 62.5%

3 0
3 years ago
Julie and mark are selling wrapping paper for a school fundraiser. Julie sold 13 rolls of plain wrapping paper and 8 rolls of ho
patriot [66]

Answer:

Cost of one roll of plain wrapping paper is $12 and Cost of one roll of holiday paper is $17.

Step-by-step explanation:

Solution,

Let the cost of 1 plain wrapping paper be x.

And the cost of 1  holiday paper be y.

Julie sold 13 rolls of plain wrapping paper and 8 rolls of holiday paper and earns $292.

Total Money earned by Julie is equal to sum of number of wrapping paper multiplied with cost of wrapping paper and number of holiday paper multiplied with cost of holiday paper.

So we can frame it in equation form as;

13x+8y=292\ \ \ \ \ equation\ 1

Now, Mark sold 7 rolls of plain wrapping paper and 2 rolls of holiday paper and earns $118.

Total Money earned by Mark is equal to sum of number of wrapping paper multiplied with cost of wrapping paper and number of holiday paper multiplied with cost of holiday paper.

So we can frame it in equation form as;

7x+2y=118\ \ \ \ \ equation\ 2

Now Multiplying equation 2 by 4 we get;

4(7x+2y)=118\times4\\\\4\times7x+4\times2y=118\times4\\\\28x+8y= 472 \ \ \ \ equation\ 3

Now Subtracting equation 1 from equation 3.

(28x+8y)-(13x+8y)= 472-292\\\\28x+8y-13x-8y= 180\\\\15x=180\\\\x=\frac{180}{2} = \$12

Now substituting the value of x in equation 1 we get;

13x+8y=292\\\\13\times12+8y=292\\\\156+8y=292\\\\8y=292-156\\\\8y=136\\\\y=\frac{136}{8}= \$17

Hence Cost of one roll of plain wrapping paper is $12 and Cost of one roll of holiday paper is $17.

8 0
3 years ago
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