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avanturin [10]
3 years ago
5

There are 112 seats in the school auditorium there are 7 seats in each row there are 70 people seated filling up full rows of se

ats how many rows are empty
Mathematics
1 answer:
irina [24]3 years ago
3 0
6 rows
112/7=16
70/7=10
16-10=6
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A real estate company is interested in the ages of home buyers. They examined the ages of thousands of home buyers and found tha
egoroff_w [7]

Answer:

Between 21 years and 75 years

Step-by-step explanation:

Given that a real estate company is interested in the ages of home buyers. They examined the ages of thousands of home buyers and found that the mean age was 48 years old, with a standard deviation of 9 years.

X the ages of home buyers is N(48, 9)

a) 30\leq x\leq 66\\|x-48|\leq 18\\|x-48|\leq 2\sigma

Hence using Cheby chev inequality

P(|x-48|\leq 2\sigma)\geq 1-\frac{1}{2^2} \\=0.75

b) 25.5\leq x\leq 70.5\\|x-48|\leq 22.5\\|x-48|\leq 1.5\sigma

P(|x-48|\leq 1.5\sigma)\geq 1-\frac{1}{1.5^2} \\=0.556

c) Using normal distribution we have

P(|x-48|\leq 2\sigma)=0.95

d) z value is 2.97

Hence x lies between

(48-9*2.97, 49+9*2.97)\\=(21.27,74.73)

Between 21 years and 75 years

4 0
3 years ago
What is the solution to the following system?
leva [86]

Answer:

(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

\left[\begin{array}{cccc}3&2&1&20\\1&-4&-1&-10\\2&1&2&15\end{array}\right]

Now I will shift rows to make my pivot point (top left) a 1 and so:

\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]

Next I will come up with algorithms that can cancel out numbers where R1 means row 1, R2 means row 2 and R3 means row three therefore,

-2R1+R2=R2 , -3R1+R3=R3

\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]

\frac{R_2}{9}=R_2


\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]


4R2+R1=R1 , -14R2+R3=R3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]


-\frac{9}{20}R_3=R_3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]


-\frac{4}{9}R_3+R_2=R2 , -\frac{7}{9}R_3+R_1=R_1


\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]


Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to".  Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

7 0
3 years ago
During a mayoral election, candidate A spent $960,000 on her campaign, and candidate B spent
Thepotemich [5.8K]

Answer:

I think it is 4:3

Step-by-step explanation:

From $960,000 take away $720,000 and you get $240,000 and that $960,000 divide by $240,000 and you get 4 and you do the same with $720,000 and you get 3

6 0
3 years ago
Soit trois nombres consécutifs. Lorsque l’on soustrait le double du deuxième nombre du quadruple du
irina [24]

Answer:

Les trois nombres sont 5, 6 et 7.

Step-by-step explanation:

Soit x le premier nombre.

x + 1 sera le second et x + 2 sera le troisième.

On pose l'équation :

2x + 3(x + 1) = 4(x + 2)

2x + 3x + 3 = 4x + 8

5x - 4x = 8 - 3

x = 5

4 0
3 years ago
If n+h/5=f+9/9, then n/5=
Ann [662]
------------------------------------------------------------------
Question
------------------------------------------------------------------
\boxed { \frac{n+h}{5}  =  \frac{f+9}{9}}

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
\boxed { \frac{n}{5} + \frac{h}{5}  = \frac{f + 9}{9}}

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
\boxed { \frac{n}{5}  = \frac{f+9}{9} - \frac{h}{5}}

------------------------------------------------------------------
Change the denominator to be the same
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}

------------------------------------------------------------------
Put it into single fraction
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }


\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}

6 0
3 years ago
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