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3 years ago

A(n) in the money supply will cause interest rates to decrease, which, in

1 answer:

5 0

A. Increase, increase
If there is more money, the less interest (less money needed to charge) when interests down, more money available spending will increase

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Is this a parallelogram? Just checking

natka813 [3]

Answer:

Step-by-step explanation:

Yes it’s parallel because the lines do not meet

8 0

3 years ago

I need help....Does anybody know the answer?

Alex_Xolod [135]

Answer:

4/5

Step-by-step explanation:

8/15 = 8/15

3/5 = 9/15

2/3 = 10/15

11/15 = 11/15

We see that the pattern is that the terms increase by 1/15 as they move up.

Thus, the next term in the sequence is 12/15, which can be simplified to 4/5.

Let me know if this helps!

3 0

2 years ago

Which of the following are ways whole numbers and rational numbers are different? Select all that apply. ︎whole numbers are a su

mihalych1998 [28]

Answer:

asd

Step-by-step explanation:

asd

8 0

2 years ago

Linsay was going to visit her grandmother shop at the mall and then return home the route she took was in the shape of a triangl

frez [133]

Answer:

an equilateral triangle

Step-by-step explanation:

A triangle is a three-sided polygon with three edges and three vertices. the sum of angles in a triangle is 180 degrees

Area of a triangle = 1/2 x base x height

the perimeter of a triangle = sum of the side lengths

An equilateral triangle is a triangle with three equal sides. the distance travelled her all equal to 10 miles.

8 0

2 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago