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3 years ago

The graph shows a proportional relationship. what is the constant proportionality?

Mathematics

1 answer:

Drupady [299]3 years ago

5 0

Answer:

Step-by-step explanation:

21 is the constant of proportionality.

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Tobias’s closet has 1 red hat and 1 black hat; 1 white shirt, 1 black shirt, and 1 black-and-white-striped shirt; and 1 pair of

forsale [732]

Answer:

There are total 12 outfit combinations.

Step-by-step explanation:

Number of hat are: 2

1 red hat and 1 black hat

Number of shirt are: 3

1 white shirt , 1 black shirt , 1 black-and-white striped shirt.

Number of pants are: 2

1 black and 1 blue

Now, the total number of combinations could be seen with the help of a tree diagram.

We observe that total 12 combinations are possible.

5 0

3 years ago

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A survey of patients at a hospital classified them by sex and blood type, as shown in the table. What percent of all patients ar

soldier1979 [14.2K]

<span>C.) 53.1% is the answer

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4 years ago

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WHAT is the answer? Pls Time limit

Law Incorporation [45]

Answer:

11 is the answer.....

Step-by-step explanation:

6x-15+39+90 = 180

7 0

3 years ago

TW¯¯¯¯¯¯¯¯¯=3, CW¯¯¯¯¯¯¯¯¯=x, TU¯¯¯¯¯¯¯=x+7, VW¯¯¯¯¯¯¯¯¯=6. Find the value of x.

belka [17]

Answer:

x = 4

Step-by-step explanation:

TW = 3

WU = TU - TW = x + 7 - 3 = x + 4

CW = x

VW = 6

By the property of intersecting chords inside a circle, we have:

TW * WU = CW * VW

3(x + 4) = x * 6

3x + 12 = 6x

12 = 6x - 3x

12 = 3x

12/3 = x

4 = x

x = 4

8 0

4 years ago

I am lost on what to do

Neko [114]

$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}$

$\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0$

4 0

4 years ago