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malfutka [58]
3 years ago
11

The graph of a linear equation passes through three of these points: (0, 5), (2, 2), (3, 1), and (4, -1).

Mathematics
1 answer:
Serggg [28]3 years ago
3 0

Answer:

The point that the graph does not pass through is (3,1)

Step-by-step explanation:

we have

(0, 5), (2, 2), (3, 1), and (4, -1)

Draw the points, and join them to plot the linear equation and determine which point does not belong to the line.

using a graphing tool

see the attached figure

therefore

The point that the graph does not pass through is (3,1)

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Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that \overleftrightarrow{FG} and \overleftrightarrow{AB} are perpendicular.

The two statements if true that guarantee  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB} are;

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Reasons:

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Required:

The two statements that guarantee that  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}.

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Therefore;

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Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

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