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dolphi86 [110]
2 years ago
7

Help please thanks Xxxxx

Mathematics
1 answer:
lions [1.4K]2 years ago
4 0

Answer:

C

Step-by-step explanation:

are you sure that this is Middle School it seems like Elementary -_-

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Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12
miskamm [114]

keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4

3 0
3 years ago
During a science experiment, the temperature of the solution in beaker one was 5° below zero. The temperature of a solution in b
Lana71 [14]
<span>5° below zero is -5 degrees
</span><span>The temperature of a solution in beaker two what is the opposite of the temperature in beaker one so it's 5 degrees above zero
</span>
answer
<span>5° above zero</span>
4 0
3 years ago
Plz Help me I don't understand
Anettt [7]

Answer:

what does the picture say?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
There are 14 students in an art class. Mr.
Alexus [3.1K]
You take the number of the colored pencils and divides it with the people in the class.

350/14 = 25
4 0
3 years ago
What is the solution to the system of equations?
elixir [45]

Answer:

No solution

Step-by-step explanation:

-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\

Lets consider the equation 2.

Here we multiply the LHS and RHS with (-1).

-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\

Hence,

-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\

When we add the equations we get,

0x+0y+0z=-10+9\\Hence,\\0=-1

As 0 doesn't equal to -1, answer is d) No solution

6 0
2 years ago
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