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2 years ago

Help please thanks Xxxxx

Mathematics

1 answer:

lions [1.4K]2 years ago

4 0

Answer:

Step-by-step explanation:

are you sure that this is Middle School it seems like Elementary -_-

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I NEED HELP WITH PERCENT PROBLEM

fomenos

Answer:

76$

Step-by-step explanation:

114=.6y; y= original price

y=190, original price

190-114=76

4 0

2 years ago

Write 337,060 in expanded form using exponent

mario62 [17]

Expanded Exponential Form:

3 × $10^{5}$ +3 × $10^{4}$ +7 × $10^{3}$ +0 × 1 $10^{2}$ +6 × $10{1}$ +0 × $10^{0}$ 

Add as Brainliest answer when you get the chance to :)

5 0

3 years ago

Read 2 more answers

Which polygon has an interior angle sum of 1260°?

Liono4ka [1.6K]

Answer:

Step-by-step explanation:

Sum of interior angle of any polygon =(n-2) × 180°where n represents the number of sides in any polygon.

Or 1260 =(n-2)x180

Dividing both sides by 180:

7=n-2

Adding both sides by 2 we have :

n=9.

Hence a nanogon will have the sum of interior angles as 1260°.

5 0

3 years ago

Read 2 more answers

3. For the graph, complete the following: (a) Write a table of ordered pairs from the graph. (b) Write an equation from the tabl

alexandr1967 [171]

for this i am working on this um please wait

6 0

2 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: