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satela [25.4K]
3 years ago
11

How does changing the amplitude affect the wavelength

Chemistry
2 answers:
Aleksandr-060686 [28]3 years ago
3 0

Answer:

If the frequency increases, then the wavelength will be shorter, because there are more waves closer together. How does changing the amplitude affect wavelength? Amplitude does not affect wavelength. ... A wave with more energy has a higher up crest/ higher amplitude.

Explanation:

astra-53 [7]3 years ago
3 0

Answer:

Increasing one decreases the other.

Explanation:

You only have so much space, so you can either have weak but frequent waves, or strong but infrequent ones.

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How come sedimentary rock become metamorphic rock
seraphim [82]
It may somehow wind up in a valcano next to the magma chamber.
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Calculate the number of atoms of H in 22.5g of H2O
Marta_Voda [28]
2.5gm answer ....2/18x22.5
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How should students prepare to use chemicals in the lab? Select one or more: Sort the lab chemicals in alphabetical order for qu
maksim [4K]

Answer:

Sort the lab chemicals in alphabetical order for quick access.

Become familiar with the chemicals to be used, including exposure or spill hazards.

Locate the spill kits and understand how they are used.

Explanation:

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The properties of each chemical should be known especially hazards connected to exposure or spill of the chemicals.

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7 0
3 years ago
Why atoms in our body don’t <br><br>eject electrons?​
Zolol [24]

Answer:

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In an atom, there is a nucleus made up of neutral charged, neutrons, and positively charged protons. The reason why electrons which are negatively charged, don't fly off is due to its stronger attraction to the protons. ... This, however, still allows the electrons to move around the nucleus of an atom.

5 0
3 years ago
How many moles of NaCl will react completely with 18.5 L F2 gas at 300.0 K and 1.00 atm?
meriva
Hello!

Data:

P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)

Apply the data to the Clapeyron equation (ideal gas equation), see:
P*V = n*R*T

1*18.5 = n*0.082*300

18.5 = 24.6n

24.6n = 18.5

n =  \dfrac{18.5}{24.6}

\boxed{\boxed{n \approx 0,752\:mol}}\end{array}}\qquad\checkmark

Note: If the feedback is to be considered, the closest response is 0.751 mol Nacl

_________________
_________________

I hope this helps. =)


3 0
3 years ago
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