So... the radiator has 15 liters of 70% antifreeze.. but needs an 80% antifreeze
well, so, you need to drain some and put some with higher percentage, seems to be, you will end up at the same 15 liters, possible the radiator's capacity, of 80% antifreeze
so, the same amount going out, of 70% is the same amount going in, of 100% antifreeze
now.. let's use the decimal format for the percents, or 70% is 70/100 or 0.7 and so on
![\bf \begin{array}{lccclll} &amount&concentration& \begin{array}{llll} concentration\\ amount \end{array}\\ &-----&-------&-------\\ \textit{70\% sol'n, out}&x&0.7&0.7x\\ \textit{100\% sol'n, in}&x&1.00&x\\ \textit{current 70\% sol'n}&15&0.7&10.5\\ -----&-----&-------&-------\\ mixture&15&0.8&12 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blccclll%7D%0A%26amount%26concentration%26%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Aconcentration%5C%5C%0Aamount%0A%5Cend%7Barray%7D%5C%5C%0A%26-----%26-------%26-------%5C%5C%0A%5Ctextit%7B70%5C%25%20sol%27n%2C%20out%7D%26x%260.7%260.7x%5C%5C%0A%5Ctextit%7B100%5C%25%20sol%27n%2C%20in%7D%26x%261.00%26x%5C%5C%0A%5Ctextit%7Bcurrent%2070%5C%25%20sol%27n%7D%2615%260.7%2610.5%5C%5C%0A-----%26-----%26-------%26-------%5C%5C%0Amixture%2615%260.8%2612%0A%5Cend%7Barray%7D)
so.. let's subtract, from the current solution, 0.7x and add 1x or x, our antifreeze concentration amount, should be 12 though
10.5 - 0.7x + x = 12
solve for "x"
Answer:
c. 14p-8
Step-by-step explanation:
8p+2(3p-4)
8p+6p-8
(8p+6p)-8
14p-8
A 10-foot ladder leans against a wall. It hits the wall 9 feet up. How far is the base of the ladder from the wall? Apply the Pythagorean Theorem to this problem
triangle
side S1 = 9 feet
hypotenuse H = 10 feet
side S2 - X = ?
the Pythagorean Theorem
H x H = S1 x S1 + S2 x S2 = S1 x S1 + X x X
X x X = H x H - S1 x S1 = 10 x 10 - 9 x 9 = 100 - 91 = 9
X x X = 9
X = 3
How far is the base of the ladder from the wall? 3 feet
check:
H x H = S1 x S1 + X x X
10 x 10 = 9 x 9 + 3 x 3
100 = 91 +9 = 100
Answer:
Uncertain if the second term is 30 and not 3o. IF 30, then the coefficients are
-1, 30 and 6.
Step-by-step explanation:
Coefficients are numbers ahead of the variables (<em>letters</em>).
The number 4 is called a constant. A constant is not a coefficient.
The coefficient (number ahead of the letters) of -xyz is -1.
Hope this helps.
Answer: The answer is c log4(x+6)=log4 16
Step-by-step explanation: