The answer I believe is -2. Thank you come again
Answer:
we have the equation y = (1/2)*x + 4.
now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:
f(4) = 6.
if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).
If we want to construct f(x), an easy example can be:
f(x) = y = k*x.
such that:
6 = k*4
k = 6/4 = 3/2.
then the function
f(x) = y= (3/2)*x intersects the equation y = (1/2)*x + 4 in the point (4, 6)
I'm assuming there is a graph with both functions plotted. The solution would be the point at which these two functions intersect. That coordinates of x and y for that point will yield the solutions for x and y that solve the system of equations.
y=kx+b
for (7,-8): -8=7k+b. (function 1)
for (-4,6): 6=-4k+b (function 2)
Use function 2 - function 1
we get: 14=-11k
k=-14/11------>slope is -14/11
Now we know that first two options are wrong since they have the wrong slope for the function.
Plus -14/11 back to function 1/ or 2. Both are correct and can give you the answer. In this case I would plug it back to function 2.
6=14*4/11+b
b=66/11-56/11
b=10/11
We get y=-14/11x+10/11
subtract both side by 6.
y-6=-14/11x+10/11-66/11
y-6=-14/11x-56/11
y-6=-14/11(x+4)
So C is correct
