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3 years ago

Suppose a triangle has two sides of length 42 and 35, and that the angle

Mathematics

2 answers:

lys-0071 [83]3 years ago

6 0

yeah he/she is right ..................

maxonik [38]3 years ago

5 0

9514 1404 393

Answer:

c = √(42² +35² -2·42·35·cos(120°))

Step-by-step explanation:

The third side can be found using the Law of Cosines. It will tell you ...

c² = a² +b² -2ab·cos(C)

where C is the angle opposite the third side (c). For the given side lengths, then the third side can be found from ...

c = √(42² +35² -2·42·35·cos(120°))

Additional comment

You have not provided answer choices to this "which ..." problem. So the above equation may be different from any on your list. We expect your answer choices may leave the equation in the form c² = ....

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Gabrielle was out at a restaurant for dinner when the bill came. His dinner came to $20. After adding in a tip, before tax, he p

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Answer:

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Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Complete:3/4 times 20 equal 5/6 times what?

vovikov84 [41]

3/4 × 20 = 5/6y
60/4 = 5/6y
360 = 30y
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3 years ago

The figure shows square KLMN. Which of the following conditions satisfy the criteria for squares?

BartSMP [9]

Answer:

First option: Square $KLMN$ with diagonals $LN$ and $KM$ .

Fifth option: Segment $LM$ is parallel to segment $KN$ .

Step-by-step explanation:

We know that a square is quadriteral whose sides are equal.

By definition, a square has the following properties:

1) Its four sides are congruent.

2) The diagonals are congruent.

3) The angles formed by the intersection of the diagonals measure 90 degrees.

4) The opposite sides are parallel.

5) Each internal angle measures 90 degrees.

Notice in the figure that:

The diagonals of the square $KLMN$ are: $LN$ and $KM$ .

$LM$ and $KN$ are opposite sides, therefore, they are parallel.

7 0

3 years ago

Read 2 more answers

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OLEGan [10]

2nd answer.

any pts in the shaded region satisfies your simultaneous equation.

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3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

NO SOLUTION

7 0

3 years ago