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Katena32 [7]
3 years ago
15

ZX is perpendicular bisector of WY if WY=24 what is WX

Mathematics
1 answer:
bixtya [17]3 years ago
6 0

Answer:

12

Step-by-step explanation:

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Seven years ago Raymond purchased a $197,000 home with a 30-year mortgage at 4.15% having recently lost his job he can no longer
tensa zangetsu [6.8K]

What’s the question ?

4 0
3 years ago
Find the largest product the positive numbers x, y, and z can have if x+y +z 2 = 16
Vikki [24]
X = 4.33333333333
y = 5.33333333333
z = 6.33333333333

3 0
3 years ago
One of the legs of a right triangle measures 7 cm and its hypotenuse measures 12 cm.
Oksana_A [137]

Answer:

AC ≈ 9,7sm

Step-by-step explanation:

AB=7  One side of a right triangle

BC=12  Hypotenuse of a right triangle

AC=?=x  The other side of a right triangle

x²+7²=12²  

x²=144-49

x²=95

x=√(95) ≈ 9,7

AC ≈ 9,7sm

3 0
2 years ago
Write each fraction as a sum or difference
vekshin1

a)\\\dfrac{17+5n}{4}=\dfrac{17}{4}+\dfrac{5}{4}n\\\\b)\\\dfrac{8-9x}{3}=\dfrac{8}{3}-\dfrac{9}{3}x=\dfrac{8}{3}-3x\\\\c)\\\dfrac{4y-12}{2}=\dfrac{4}{2}y-\dfrac{12}{2}=2y-6\\\\d)\\\dfrac{25-8t}{5}=\dfrac{25}{5}-\dfrac{8}{5}t=5-\dfrac{8}{5}t\\\\e)\\\dfrac{18x+51}{17}=\dfrac{18}{17}x+\dfrac{51}{17}=\dfrac{18}{17}x+3

5 0
3 years ago
The table below shows the heights of several books. Jean stacks a dictionary on top of her novel. How high is the stack of the t
aev [14]

<u><em>Answer:</em></u>

The height of the stack = 5\frac{1}{4} in

<u><em>Explanation:</em></u>

We are given that Jean stacks a dictionary on top of a novel.

This means that the total height of the stack will be equal to the height of the dictionary added to the height of the novel.

<u>From the givens, we have:</u>

height of dictionary = 4\frac{1}{2} in

height of novel = \frac{3}{4} in

<u>Now, adding the two height, we will have:</u>

Total height of stack = height of novel + height of dictionary

Total height of stack = \frac{3}{4}+4 \frac{1}{2} = \frac{3}{4}+ \frac{18}{4}= \frac{21}{4}=5 \frac{1}{4} in

Hope this helps :)

6 0
3 years ago
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