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Tanzania [10]
3 years ago
13

CAN ANYONE HELP PLEASE!!

Mathematics
2 answers:
icang [17]3 years ago
6 0

Answer:

b

Step-by-step explanation:

Vitek1552 [10]3 years ago
5 0
The answer is b hope you get it right and turned in
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In a bag, there are 5 cards numbered 1 to 5. Each time a card is randomly selected, it I'd replaced in the bag. What is the prob
sweet [91]

Out of 5 cards in the bag ...

-- There are 2 even numbers . . . 2 and 4 .

-- There are 3 odd numbers . . . 1, 3, and 5 .

So EITHER time, the probability of pulling an even number is  2/5 ,
and the probability of pulling an odd number is  3/5 .

The probability of pulling an even number the first time
AND an odd number the second time is

       (2/5) x (3/5)  =  6/25  =  <em>24%</em> .

 
3 0
3 years ago
Read 2 more answers
Oh mah lord please please help me
Alenkinab [10]

Option 2: 4^{\frac{1}{6}} is the correct answer.

Step-by-step explanation:

The radical expressions like these are simplified by using fractional exponents

given

\frac{\sqrt{4}}{\sqrt[3]{4} }

Converting radicals into exponents

When there is no base the exponent is 1/2 and as the base is 3, the exponent will be 1/3

So

=\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}

As the bases of numerator and denominator is same, the exponents can be subtracted

=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}

Hence,

Option 2: 4^{\frac{1}{6}} is the correct answer.

Keywords: Exponents, radicals

Learn more about radicals at:

  • brainly.com/question/6073431
  • brainly.com/question/6075514

#LearnwithBrainly

7 0
3 years ago
8 to 14 as a ratio as a fraction in simplest form.
padilas [110]

Answer:

4/7 or 4:7

Step-by-step explanation:

8/14 divided by 2= 4/7

3 0
3 years ago
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What do you notice about the table inputs for the graph of √x?
Airida [17]

Answer:

See below

Step-by-step explanation:

When we talk about the function f(x)=\sqrt{x}, the domain and codomain are generally defaulted to be subsets of the Real set. Once $f:[0,\infty)\to [0,\infty)$ and  $f\subseteq [0,\infty)\times [0,\infty)$ such that $(x,y_1)\in f\wedge(x,y_2)\in f \Rightarrow y_1=y_2$  for $f(x)=\sqrt x$. Therefore,

\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]

\[x \mapsto \sqrt{x}\]

But this table just shows the perfect square solutions.

4 0
2 years ago
Which explains whether sophia is correct
IgorLugansk [536]

Answer:

uhh where's the rest of the question hombre

7 0
2 years ago
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