Out of 5 cards in the bag ...
-- There are 2 even numbers . . . 2 and 4 .
-- There are 3 odd numbers . . . 1, 3, and 5 .
So EITHER time, the probability of pulling an even number is 2/5 ,
and the probability of pulling an odd number is 3/5 .
The probability of pulling an even number the first time
AND an odd number the second time is
(2/5) x (3/5) = 6/25 = <em>24%</em> .
Option 2:
is the correct answer.
Step-by-step explanation:
The radical expressions like these are simplified by using fractional exponents
given
![\frac{\sqrt{4}}{\sqrt[3]{4} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B4%7D%7D%7B%5Csqrt%5B3%5D%7B4%7D%20%7D)
Converting radicals into exponents
When there is no base the exponent is 1/2 and as the base is 3, the exponent will be 1/3
So

As the bases of numerator and denominator is same, the exponents can be subtracted

Hence,
Option 2:
is the correct answer.
Keywords: Exponents, radicals
Learn more about radicals at:
#LearnwithBrainly
Answer:
4/7 or 4:7
Step-by-step explanation:
8/14 divided by 2= 4/7
Answer:
See below
Step-by-step explanation:
When we talk about the function
, the domain and codomain are generally defaulted to be subsets of the Real set. Once
and
such that
for
. Therefore,
![\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%5Ccdot%7D%3A%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5Cto%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5C%5D)
![\[x \mapsto \sqrt{x}\]](https://tex.z-dn.net/?f=%5C%5Bx%20%5Cmapsto%20%5Csqrt%7Bx%7D%5C%5D)
But this table just shows the perfect square solutions.
Answer:
uhh where's the rest of the question hombre