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stepan [7]
2 years ago
10

PLEASE HELP

Mathematics
1 answer:
ehidna [41]2 years ago
3 0
You can find the answer by plugging in any of the multiple choice options into a,
when you square a number (^2), the result is always positive even if the number starts off negative, 
 -25 or 125 wouldn't work for this equation because the answer is too big
but when you plug -5 or 5 in you get the right answer, so the answer is c
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12.5*<img src="https://tex.z-dn.net/?f=12.5%20%2A17.9%3D" id="TexFormula1" title="12.5 *17.9=" alt="12.5 *17.9=" align="absmiddl
kkurt [141]
The answer is 223.75 because you multiply 12.5 and 17.9
5 0
3 years ago
Simplify the radical expression.
levacccp [35]

Answer:

9√3

Step-by-step explanation:

√(81*3)

√81*√3

9√3

6 0
2 years ago
Find the GCF of the following set of numbers <br> 260, 80, 50
Vinvika [58]

Answer:

10

Step-by-step explanation:

The factors of 50 are: 1, 2, 5, 10, 25, 50

The factors of 80 are: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factors of 260 are: 1, 2, 4, 5, 10, 13, 20, 26, 52, 65, 130, 260

In all of these numbers, we can see that 10 is common throughout and 10 is also the greatest factor all these numbers share.

Hope this helps you :)

7 0
3 years ago
Read 2 more answers
Select the appropriate property of equality for the statement. If a = b, then a + c = b + c.
Liula [17]

A. ) Addition Property is the answer


5 0
3 years ago
Two boats left a base camp at bearing of S60°E and S50°W at speeds of 50km/h and 70km/h respectively. Find the distance between
ivolga24 [154]

Answer:

  • 197.93 km

Step-by-step explanation:

Let the base camp is point A and boats' locations after two hours are points B and C.

By connecting the three points together we get a triangle ABC with sides:

  • AB = 50*2 = 100 km
  • AC = 70*2 = 140 km

The angle between AB and AC is:

  • 60 + 50 = 110 degrees (opposite directions from south)

We are looking for the distance BC, which can be found by using the law of cosines:

  • BC² = AB² + AC² - 2AB*AC*cos ∠BAC
  • BC² = 100² + 140² - 2*100*140*cos 110°
  • BC²  = 39176.56 (rounded)
  • BC = √39176.56 = 197.93 km (rounded)

The distance between the boats is 197.93 km.

7 0
1 year ago
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