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horsena [70]
3 years ago
11

Can anyone help me please heheh

Mathematics
2 answers:
svetoff [14.1K]3 years ago
6 0

Answer:

sqrt160

Step-by-step explanation:

Umnica [9.8K]3 years ago
5 0
I think it should be 3
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HELP, ASAP! Given that lines b and c are parallel, SELECT ALL THAT APPLY. Which pairs of angles are vertical angles?
mart [117]
2 and three and 4 and 5!
5 0
3 years ago
There are 20 juice cups and each juice cup holds 10 fluid ounces. the juice comes in 1 gallon bottles. how many 1 gallon bottles
Andru [333]
20 times 10=200 fluid ounces

128 fluid ounces per gallon
1 gallon is too little
2 gallons is to much
but  you can't buy 1 and 72/100 of a bottle so just buy 2

2 bottles
6 0
3 years ago
Find all zeros of function and write the polynomial as a product of linear factorsX^3-x^2+9x-9
mart [117]

Answer:

\large\boxed{x=1\ \vee\ x=-3i\ \vee\ x=3i}

Step-by-step explanation:

\text{The zeros:}\\\\x^3-x^2+9x-9=0\\\\x^2(x-1)+9(x-1)=0\\\\(x-1)(x^2+9)=0\iff x-1=0\ \vee\ x^2+9=0\\\\x-1=0\qquad\text{add 1 to both sides}\\x-1+1=0+1\\\boxed{x=1}\\\\x^2+9=0\qquad\text{subtract 9 from both sides}\\x^2=-9

8 0
3 years ago
Find thhe remainder when 7^203 is divided by 4
Aleksandr [31]
Using the square-and-multiply approach, we have

7^{203}=7\times(7^{101})^2
7^{101}=7\times(7^{50})^2
7^{50}=(7^{25})^2
7^{25}=7\times(7^{12})^2
7^{12}=(7^6)^2
7^6=(7^3)^2
7^3=7\times7^2

and so, using the property that, if a_1\equiv b_1\mod n and a_2\equiv b_2\mod n, then a_1a_2\equiv b_1b_2\mod n, we get

7\equiv3\mod4
7^2\equiv9\equiv1\mod4
7^3\equiv7\times1\equiv7\equiv3\mod4
7^6\equiv9\equiv1\mod4
7^{12}\equiv1\mod4
7^{25}\equiv7\times1\equiv7\equiv3\mod4
7^{50}\equiv9\equiv1\mod4
7^{101}\equiv7\times1\equiv7\equiv3\mod4
7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4
4 0
3 years ago
I need help and i need it fast TIME DUE 4 MIN
Phoenix [80]

Answer:

18

Step-by-step explanation:

multyply both like 10 x 6 then 11 x 7 after that subtrac the numbers that you múltiple and you will get the answer

8 0
3 years ago
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