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RideAnS [48]
3 years ago
8

Explain why the exponents cannot be added in the product 12^3 x 11^3.

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

The exponents can only be added if the bases are the same

Here one base is 12 and the other is 11

So the rule of addition is not applicable.

stepladder [879]3 years ago
3 0

Answer:

Because the bases (12 and 11) are different.

Step-by-step explanation:

You can only add exponents when the bases are the same.

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Larina received a 50$ gift card to an online store. She wants to purchase some bracelets that cost 8$ each. There will be an ove
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8n+10=50 <-- Original Equation

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n=5 <-- Use Division Property of Exponents to remove the 8 from the n and find the unit of n

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4 years ago
What’s the answer to this
Fed [463]

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This is the wrong subject. and please provide a passage.

Step-by-step explanation:

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3 years ago
Divided 80 by my number, and then added 13. The result was 93. What was my number?
igor_vitrenko [27]

The number is 6400.

We have given that,

divided 80 by my number, and then added 13.

<h3>What is the expression?</h3>

An expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Suppose the number is x

\frac{x}{80}+13=93

Subtract  13  from both sides

\frac{x}{80}+13-13=93-13

\frac{x}{80}=80

Multiply both sides by 80

\\\frac{80x}{80}=80\cdot \:80

x=6400

Therefore the number is 6400.

To learn more about the number visit:

brainly.com/question/251701

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4 0
2 years ago
Write an equation for a line parallel to y=-3x-5 and passing through the point (4,-16)
const2013 [10]

Answer:

Insert the numbers into the equation y=3x-5.

the rule states that in every equation the first number is x.so it will be -6=3(4)-5

-6=12-5

-6=7.

If u want, you can leave your answer like that

3 0
3 years ago
What is the length of the altitude of the equilateral triangle below?
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\bf \textit{height or altitude of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2}~~ \begin{cases} s=\stackrel{length~of}{a~side}\\ \cline{1-1} s=8\sqrt{3} \end{cases}\implies h=\cfrac{8\sqrt{3}\cdot \sqrt{3}}{2}\implies h=\cfrac{8\sqrt{3^2}}{2} \\\\\\ h=4\cdot 3\implies h=12

3 0
3 years ago
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