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RideAnS [48]
2 years ago
8

Explain why the exponents cannot be added in the product 12^3 x 11^3.

Mathematics
2 answers:
sergij07 [2.7K]2 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

The exponents can only be added if the bases are the same

Here one base is 12 and the other is 11

So the rule of addition is not applicable.

stepladder [879]2 years ago
3 0

Answer:

Because the bases (12 and 11) are different.

Step-by-step explanation:

You can only add exponents when the bases are the same.

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Need help simple explanation if possible
photoshop1234 [79]

Answer:

m < A = 60º

m < B = 30º

Step-by-step explanation:

The given sides on this triangle are: 6, 6\sqrt{3}, and 12

Any triangle with the angles of 30º - 60º - 90º always has side lengths in this proportion:

x, x\sqrt{3}, 2x

We can line this up with the given sides. If x is 6, then 2x would be 12.

x : x\sqrt{3} : 2x = 6 : 6\sqrt{3} : 12

Angle B is across from 6, the shortest side. That also means that it corresponds to x, or the smallest angle in the proportion, 30º.

m < B = 30º

Solving for < A:

Method 1) Sum of Angles in a Triangle

Since we already know that one angle is right and therefore 90º and m < B is 30º, we can subtract these from the total sum of angle measures in a triangle to get the last angle, < A.

180º - 90º - 30º = 60º

m < A = 60º

Method 2) Using the second part of the proportion

Since m < A is across from the second largest side, we know that it is equal to x\sqrt{3} (6\sqrt{3} in this question) or 60º in the angle proportion.

This means that m < A = 60º

Let me know if you have any questions!

4 0
2 years ago
Read 2 more answers
a bottle of juice holds 3/8 gallon when it is full. if 1/3 of the juice has been poured out, how much juice is left in the bottl
taurus [48]
Let's get the denominators of both fractions to be the same before moving on, aka finding the least common multiple of the denominators.

8 and 3 have a LCM of 24. So, we have to multiply 1/3 by 8 and 3/8 by 3.

1/3 * 8/8 = 8/24

3/8 * 3/3 = 9/24

There is only 1/24 of juice left in the bottle if the remaining amount of juice has 1/3 poured out.

Hope that helped.
4 0
3 years ago
Please help stuck on probelem
Maurinko [17]
<h3>Answer:  36 square units</h3>

=========================================================

Explanation:

Draw a horizontal line to cut the figure into a rectangle on top and a triangle down below.

The rectangle has length and width of 6 and 4 (horizontal and vertical components respectively). The area of this rectangle is 6*4 = 24 square units.

The triangle has a base of 6 and a height of 4. The base and height of any triangle are always perpendicular.

The area of the triangle is base*height/2 = 6*4/2 = 24/2 = 12 square units. If you were to cut out half of the triangle and rearrange things, you'll find that a rectangle can be formed. This rectangle is half in area that of the first rectangle we found. This is why we divide by 2 when finding the area of the triangle.

Once you know the two sub-areas, we add them up to get the overall area: 24+12 = 36 square units.

5 0
3 years ago
Read 2 more answers
Can someone explain what to do here I’m very confused?
Grace [21]
Start by distributing the - 1/3 which is the same as dividing the entire parentheses by 3 which results in (3x+10)
4 0
3 years ago
PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION
Alex17521 [72]

<u>Solution</u><u>:</u>

\sqrt{4x + 13}  = x + 2

  • First square both sides.

=  > ( \sqrt{4x + 13} ) ^{2}  = (x + 2) ^{2}

  • Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

=  > 4x + 13 =  {(x)}^{2}  + 2 \times x \times 2 + (2) ^{2} \\  =  > 4x + 13 =  {x}^{2}   + 4x + 4

  • Now, transpose 4x and 4 to LHS.

=  > 4x - 4x + 13 - 4 =  {x}^{2}  \\

  • Now, do the addition and subtraction.

=  >  {x}^{2}  = 9 \\  =  >  x =  \sqrt{9}  \\  =  > x = ±3

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>

Hope you could understand.

If you have any query, feel free to ask.

3 0
2 years ago
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