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melamori03 [73]
3 years ago
14

I AM GONNA POST MORE QUESTIONS!!!!!! I AM SO STRESSED I HATE TESTS

Mathematics
2 answers:
Troyanec [42]3 years ago
7 0

Answer:

the second statement is true

Step-by-step explanation:

Reil [10]3 years ago
7 0

Answer:

The second statement is true I think

Step-by-step explanation:

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The area of a circle is given by πr2, where r is the radius of the circle. If we use rounding to the nearest whole number, what
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75cm^2

Step-by-step explanation:

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4 0
3 years ago
Use distributive property to rewrite 3×546​
sergij07 [2.7K]

Answer:

1638

Step-by-step explanation:

3(500)+3(40)+3(6)=1500+120+18=1638

4 0
2 years ago
2.
S_A_V [24]

B)

The corect answer for this question

6 0
2 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

3 0
3 years ago
If m∠TRK equal 32.5°, what is m∠TSK?
MrRa [10]
The answer is whatever is equal to 32.5 hope this helped you
7 0
3 years ago
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