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2 years ago

I AM GONNA POST MORE QUESTIONS!!!!!! I AM SO STRESSED I HATE TESTS

Mathematics

2 answers:

Troyanec [42]2 years ago

7 0

Answer:

the second statement is true

Step-by-step explanation:

Reil [10]2 years ago

7 0

Answer:

The second statement is true I think

Step-by-step explanation:

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What number should be placed in the box to help complete the division calculation?

Anarel [89]

344 should be placed in the box

3 0

3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Please help me it is an easy question

Ugo [173]

Answer:

200 yd²

Step-by-step explanation:

A = 17 yd

B = 15 yd

C = 2 yd

D = 8 yd

b) Area of rectangle = length * width

$\sf Area \ of \ 2 \ triangle = 2* \dfrac{1}{2}* base * height = base* height\\\\$

Area of right triangular prism = Areas of two triangle + area of the upper rectangle + area of middle rectangle + area of below rectangle

= 8 * 15 + 17 * 2 + 15 *2 + 8*2

= 120 + 34 + 30 + 16

= 200 yd²

5 0

1 year ago

Jerry needs 216 posts to build a fence. He has 88 posts and needs P more. Write an equation that you could use to find the numbe

devlian [24]

Answer:

P = 128 Post

Step-by-step explanation:

Total post needed = 216 posts

Number of post Jerry has = 88 posts

Number of posts jerry still needs = P

Total = Number of post Jerry has + Number of posts jerry still needs

216 = 88 + P

216 - 88 = P

128 = P

P = 128 Post

7 0

3 years ago

PLS HELP ASAP FIRST CORRECT ANSWER GETS BRAINLIEST

Anna11 [10]

Using Pythagorean, a^2 + b^2 = c^2
16 +x^2 = 36.69
Then subtract the 16 from 36.69, which is 23.69
And finally take the square root of that, giving you 4.87

6 0

1 year ago