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givi [52]
3 years ago
11

Can someone help me with system of equations?

Mathematics
1 answer:
nignag [31]3 years ago
3 0
2x + y = 350
x + 2y = 475 
3x + 3y = 825
x + y = 275
x = 275 - y 
(plug back into first equation) 
2(275 - y) + y = 350
550 - 2y + y = 350 
550 - y = 350
-y =-200 or y = $200 (dog)
therefore, x = $75 (cats)
Check
2(75) + 200 = 350
75 + 400 = 475 
HAPPINESS! :)
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paul , Nadia and Jim have some stickers. Nadia has 3 times as many stickers as jim. Paul has 25 stickers more that Nadia. Paul a
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Nadia = 3x than Jim
Paul = 25+ than Nadia
Jim = ?
Nadia and Paul = 85

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3 years ago
An instructor wants to write a test with 25 questions where each question is worth 3, 4, or 5 points based on difficulty. He wan
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ANSWER

Find out the how many 3, 4, and 5 point questions could there be.

To proof

Let us assume that the 3 points based question be = x

Let us assume that the 4 points based question be = y

Let us assume that the 5 points based question be = z

As given

An instructor wants to write a test with 25 questions

than the equation become in the form

x + y + z = 25

he quiz to be worth a total of 100 points.

than the equation is becomes

3x + 4y + 5z =100

As given

He wants the number of 3-point questions to be 4 less than the number of 4-point questions

x = y -4

Than the three equation are

x + y + z = 25 ,3x + 4y + 5z =100 and x = y -4

put  x = y -4 in the x + y + z = 25 ,3x + 4y + 5z =100

than

2y + z = 29, 7y +5z= 112

multiply 2y + z = 29 by 5 and subtracted 7y +5z= 112

10 y -7y + 5y -5y = 145 -112

3y = 33

y = \frac{33}{3}

y =11

put in the  x = y -4

x = 11-4

x= 7

put the value of x ,y in the x + y + z = 25

7 + 11 +z =25

18 +z = 25

z = 25 -18

z=7

therefore

numbers of the 3 point question be = 7

numbers of the 4 point question be = 11

numbers of the 5 point question be = 7

Hence proved



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