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harkovskaia [24]
3 years ago
15

Three pounds of fish food costs $14.97 at the market. What is the unit price

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0

Answer: $4.99

Step-by-step explanation:

14.97 ÷ 3; this will tell you the unit price of each individual fish.

The answer is $4.99.

***If you found my answer helpful, please give me the brainliest. :) ***

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The square of a positive number decreased by twice the number is 48. Find the number
barxatty [35]
The number is 8.
8^2-16=48
7 0
3 years ago
Can someone help me with this i don’t understand at all
Sedbober [7]

Answer:

Use trig

Step-by-step explanation:

sin(55) = x/21

x = 21sin(55)

use calculator in degree mode

cos(55) = y/21

21cos(55) = y

5 0
3 years ago
What is the percent change of $15.60 to $11.70?
Rashid [163]

Answer:

percentage change=25% .

Step-by-step explanation:

Given : $15.60 to $11.70    .

To find:  What is the percent change .

Solution: We have given that   $15.60 to $11.70  .

Change = final value - initial value .

Change   = $15.60 - $11.70  

                   =$3.9

percentage change = \frac{change}{original value}*100

                                =   \frac{3.9}{15.60}*100

                                =   \frac{390}{1560}*100.

On dividing both number by 3

percentage change=\frac{130}{520}*100.

percentage change=\frac{1}{4}*100.

percentage change=25% .

Therefore, percentage change=25% .

5 0
3 years ago
Read 2 more answers
I need help due tmrw
White raven [17]

Answer:

yo ill help you but do you happen to have a argumentative essay written ill help u if you help me

3 0
2 years ago
(sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^
ArbitrLikvidat [17]
(sin\theta+sec\theta)^2+(cos\theta+cosec\theta)^2=(1+sec\theta\ cosec\theta)^2\\\\L=sin^2\theta+2sin\theta\cdot\frac{1}{cos\thewta}+\frac{1}{cos^2\theta}+cos^2\theta+2cos\theta\cdot\frac{1}{sin\theta}+\frac{1}{sin^2\theta}\\\\=(sin^2\theta+cos^2\theta)+\frac{2sin\theta}{cos\theta}+\frac{2cos\theta}{sin\theta}+\frac{1}{cos^2\theta}+\frac{1}{sin^2\theta}

=1+\frac{2sin^2\theta+2cos^2\theta}{sin\theta\ cos\theta}+\frac{sin^2\theta+cos^2\theta}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2(sin^2\theta+cos^2\theta)}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1^2+2sec\theta\ cosec\theta+sec^2\theta\ cosec^2\theta\\\\=(1+sec\theta\ cosec\theta)^2=R
4 0
3 years ago
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