Answer:
Step-by-step explanation:
1. Divide the coefficients and the exponentials separately
2. Divide the coefficients
3. Divide the exponentials
Subtract the exponent in the denominator from the exponent in the numerator.
4. Re-join the new coefficient and the new exponential
5. Put the new number into standard form
The number before the power of 10 must be greater than or equal to one and less than 10.
Multiply the answer by 10/10.
Answer:
1 mi/hr
Step-by-step explanation:
Given that:
Speed in still water, s = 5 mi/hr
Let speed of current = x
Time = distance /speed
Upstream (subtract speed of current) = 5 - x
Upstream time = 8 / 5 - x - - - (1)
Downstream (add speed of current) = 5 + x
Downstream time = 12 / 5 + x - - - (2)
Equate (1) and (2)
8 / (5 - x) = 12/ (5 + x)
8(5 + x) = 12(5-x)
40 + 8x = 60 - 12x
40 - 60 = - 12x - 8x
-20 = - 20x
x = 1
Spwed of current = 1 mi/hr
First you would have to add 4.8f and 6.4 to get 11.2f. (11.2f=-8.48) Next you would subtract 11.2 from each side to get your answer of -19.68z
f=-19.68
Denote the average of the six numbers as n. This will be an even number and the six odd numbers are:
<span>n−5,n−3,n−1,n+1,n+3,n+5</span>
Then:
<span>204=<span>(n−5)</span>+<span>(n−3)</span>+<span>(n−1)</span>+<span>(n+1)</span>+<span>(n+3)</span>+<span>(n+5)</span>=6n</span>
Divide both ends by 6 and transpose to find:
<span>n=<span>2046</span>=34</span>
So the six odd numbers are:
<span>29,31,33,35,37,<span>39</span></span>
