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3 years ago

How do we do with this formula? Help me with A pls

Mathematics

2 answers:

Masteriza [31]3 years ago

8 0

Answer:

find all the equation placing each one

Step-by-step explanation:

for eg in no a

gradient is 2

point is (4,1)

so the point (4,1) is (x1,y1)

using formula

y-y1=m(x-x1)

y-1=2(x-4)

y-1=2x-8

therefore 2x-y-7=0 is the required equation

now do all of the above like this

Ugo [173]3 years ago

3 0

Gradient is the slope, which is the letter m in the equation.

The point is written as (x1, y1) so replace x1 and y1 in the equation with the numbers in the given point.

A would be y - 1= 2(x-4)

B: y +5 = 5(x-2)

C: y-1= -3(x+1)

D: y -6 = 1/2(x-1)

E: y +1/4 = -2(x-3:4)

F: y+7 = -1/5(x+ 3)

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What is the measure of x? Please help!

Zepler [3.9K]

Answer:

x =√[y²+(27)²] = √[ z² - 3² +(27)²]

Step-by-step explanation:

step 1) x=√[y²+(27)²]

step 2)

We find y

z²=y²+3² → y² = z² - 3²

step 3) x = √[ z² - 3² +(27)²]

7 0

3 years ago

What is the slope of (5,8) (18,18)

Anettt [7]

Answer:

10/13

Step-by-step explanation:

Y1-Y2 / X1-X2

18-8 / 18-5

18-8 = 10

18-5 = 13

6 0

3 years ago

What is 2 to the 9th power

andrey2020 [161]

Answer:

it is 512

Step-by-step explanation:

5 0

3 years ago

Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

brainly.com/question/27419605

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7 0

2 years ago

PLEASE HELP ME (40 POINTS)

CaHeK987 [17]

For each equation give X a value and solve for Y, do this at least two times for each equation.

Plot those dots on a graph to draw two lines.

The solution is where the two lines cross.

You will see the lines cross at (-1,-2)

7 0

3 years ago

How do we do with this formula? Help me with A pls​

How do we do with this formula? Help me with A pls