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algol [13]
3 years ago
14

Me ayudan y les doy corona porfavor​

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
Sheeesh bro Thats a lot of you ask me
You might be interested in
More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q^{1} = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0
3 years ago
the times that gym members spend on a treadmill are normally distributed with a mean of 20 min and a standard deviation of 8 min
Papessa [141]
<span>Given:
xbar = 20 min
standard deviation = 8 min
total sample = 240

Required:
how many gym members are expected to spend 4 min and 36 min on a treadmill today

Solution:
sd</span>² = (∑(x - xbar)²) / N - 1

there are 42 gym members at 4 minutes and 200 gym members in 36 minutes.
6 0
3 years ago
Identify whether the equation represents an exponential growth or exponential decay function.1. y = 1/4 (1/e)^-2x2. y = (1/e)^4x
zvonat [6]

The general formula for exponential growth and decays is:

y=y_0e^{kx}

if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.

Now we need to classify each of the functions:

1.

The function

y=\frac{1}{4}(\frac{1}{e})^{-2x}

can be wrtten as:

\begin{gathered} y=\frac{1}{4}(e^{-1})^{-2x}^{} \\ =\frac{1}{4}e^{2x} \end{gathered}

comparing with the general formula we notice that k=2, therefore this is an exponential growth.

2.

The function

y=(\frac{1}{e})^{4x}

can be written as:

\begin{gathered} y=(\frac{1}{e})^{4x} \\ y=(e^{-1})^{4x} \\ y=e^{-4x} \end{gathered}

comparing with the general formula we notice that k=-4, therefore this is an exponential decay.

3.

The function

y=2e^{-x}+1

comparing with the general formula we notice that k=-1, therefore this is an exponential decay.

5 0
1 year ago
Can you guys please simplify the expressions?
Maksim231197 [3]

Here is your answer :)

5 0
3 years ago
PLEASE HELP ME!! PLEASE DON'T ANSWER IF YOU ARE NOT PSOTIVE ON WHAT THE ANSWER IS!!!
Talja [164]

Answer:

its A

Step-by-step explanation:

im not gonna step by step it becuase i dont have time but its A

5 0
3 years ago
Read 2 more answers
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