here is a image. 6th grade problem i in 6th grade. Please do part A and part B for problem 1 and also please do problem 2 so ASA
P answer it PLease! And please try people just put in random letters
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The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ==5
n=50
s orσ =5/=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
Answer is ( -3, 7)
Rule for reflection over x axis is
x , y to x, -y
Since the y value is already negative it will change to positive
See attachment
Rule for reflection over x axis is
x , y to x, -y
Since the y value is already negative it will change to positive
See attachment