Answer:
-6
Step-by-step explanation:
Answer:
the answer would be 15x+ 1
Step-by-step explanation:
What is asked here is that you isolate y so that the equation takes the form of y = ..., where ... will be something that contains a, b and c but not y. So how do we get there? By applying some standard permutations to equations like so:
aby - b = c
First, we bring the -b term to the right hand side by adding b left and right:
aby -b+b = c+b
The -b and +b cancel out, so we get:
aby = c + b
Then, we divide left and right hand side by ab:
aby/ab = (c+b)/ab
Again, the ab/ab on the left cancels out (it is 1), so we get:
y = (c+b)/ab
And we're done!
So you have to know that it is allowed to add or subtract something (anything) to/from the left and right hand side of an equation. Likewise, you have to know that it is allowed to multiply or divide by something, as long as it isn't 0.
1) The first graph is the graph of f(x) traslated 5 units to the left, then the equation of this graph is: y=(x+5)^2
2) The second graph is the graph of f(x) traslated 5 units upward, then the equation of this graph is: y=x^2+5
3) The third graph is the graph of f(x) traslated 5 units downward, then the equation of this graph is: y=x^2-5
4) The fourth graph is the graph of f(x) traslated 5 units to the right, then the equation of this graph is: y=(x-5)^2
