Question

For the function y = -2 + 5 sin (pi/12(x-2)), what is the minimum value?

Answer 1

Answer:

The maximum value is 3.

Step-by-step explanation:

The given trigonometric function is

$y=-2+5\sin(\frac{\pi}{12}(x-2))$

The amplitude of this function is 5.

$|A|=5$

$-5\le A\le5$

The function is shifted vertically down by two units.

To find the maximum value, we add -2 to the upper boundary of A.

The maximum values is 5-2=3