Answer:
it will turn out to be a repeating decimal so put a little line over the first 3 to the right of the decimal (517.8333333333)
Step-by-step explanation:
Answer:
He should pay $2,790.7.
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:
![E = P*I*t](https://tex.z-dn.net/?f=E%20%3D%20P%2AI%2At)
In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.
After t years, the total amount of money is:
![T = E + P](https://tex.z-dn.net/?f=T%20%3D%20E%20%2B%20P)
In this question:
Rate of 10%, so I = 0.1.
9 months, so ![t = \frac{9}{12} = 0.75](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B9%7D%7B12%7D%20%3D%200.75)
How much should he pay for a note that will be worth $3,000 in 9 months?
We have to find P for which T = 3000. So
![T = E + P](https://tex.z-dn.net/?f=T%20%3D%20E%20%2B%20P)
![3000 = E + P](https://tex.z-dn.net/?f=3000%20%3D%20E%20%2B%20P)
![E = 3000 - P](https://tex.z-dn.net/?f=E%20%3D%203000%20-%20P)
Then
![E = P*I*t](https://tex.z-dn.net/?f=E%20%3D%20P%2AI%2At)
![3000 - P = P*0.1*0.75](https://tex.z-dn.net/?f=3000%20-%20P%20%3D%20P%2A0.1%2A0.75)
![1.075P = 3000](https://tex.z-dn.net/?f=1.075P%20%3D%203000)
![P = \frac{3000}{1.075}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B3000%7D%7B1.075%7D)
![P = 2790.7](https://tex.z-dn.net/?f=P%20%3D%202790.7)
He should pay $2,790.7.
Answer:
the correct answer is A , D
I dont know the question sory
Answer:
um ok then nice :l
Step-by-step explanation: