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zzz [600]
3 years ago
5

ASAPPPPP how do 2 positive charge move in an electric field

Chemistry
1 answer:
Luden [163]3 years ago
4 0

Answer:

yer

Explanation:

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1. What is the state of matter of each of these materials at room temperature? a) gold b) gasoline c) oxygen d) olive oil e) mer
ehidna [41]

Answer:

a) gold - Solid

b) gasoline - liquid

c) oxygen - gaseous

d) olive oil - liquid

e) mercury (found in thermometers) - liquid

f) aluminum - solid

Explanation:

Matter exists in three states viz: solid, gas and liquid. Note that, room temperature is a neither hot or cold temperature, which is about 20-23°C.

A) Gold is a transition metal with the symbol Au. At a room temperature, Gold, like most metals are found as SOLIDS.

B) Gasoline is a liquid mixture of refined hydrocarbons majorly used as fuels.

C) Oxygen is a chemical element with symbol O. It is a constituent of natural air, which is a mixture of different gases including oxygen. Hence, at room temperature, Oxygen is a gas.

D) Olive oil is a vegetable oil got from olives. It is composed of fats and it's a liquid at room temperature.

E) Mercury is an element with symbol Hg. It is the only metallic element found naturally (at room temperature) as a liquid. It is used in thermometers.

F) Aluminum is another chemical element with symbol Al. It is a lustrous metal that occurs as a Solid in room temperature.

8 0
3 years ago
Which organelle is the control center of a cell?
Korvikt [17]
C) the nucleus. Hope this helps :)
6 0
3 years ago
Read 2 more answers
In the levels of organization of plants, What are the 2 tissues and their functions?
Valentin [98]
Vascular tissue transports water, minerals, and sugars to different parts of the plant. Vascular tissue is made of two specialized conducting tissues: xylem and phloem. Xylem tissue transports water and nutrients from the roots to different parts of the plant, and also plays a role in structural support in the stem.
4 0
3 years ago
Calculate the freezing temperature of the following solution of 0.50 M glucose (a covalent compound). Assume that the molality o
kirza4 [7]

Answer:

-0.93 °C

Explanation:

Hello,

The freezing-point depression is given by:

T_f-T_f^*=-iK_{solvent}m_{solute}

Whereas T_f is the freezing temperature of the solution, T_f^* is the freezing temperature of the pure solvent (0 °C since it is water), i the Van't Hoff factor (1 since the solute is covalent), K_{f,solvent} the solvent's freezing point depression point constant (in this case 1.86 C\frac{kg}{mol}) and m_{solute} the molality of the glucose.

As long as the unknown is T_f, solving for it:

T_f=T_f^*-iK_fm\\T_f=0C-1*1.86C\frac{kg}{mol}*0.5\frac{mol}{kg}  \\T_f=-0.93C

Best regards.

4 0
3 years ago
The light produced by fireflies is a complex
mr_godi [17]

The answer is h the reaction produces a lot of thermal energy

7 0
4 years ago
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