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3 years ago

What is the value of 1.5 ATM of gas at 20°C and a 3 L vessel are heated at 30°C at a pressure of 5.2 ATM

Chemistry

1 answer:

vampirchik [111]3 years ago

6 0

Answer:

The answer will be approximately 1.0L

Explanation:

The problem has not been properly specified. You could have specified a gas in a PISTON, whose volume would decrease with increased pressure, and increase with increased temperature.

For such a system, we would use the

combined gas law:

$\frac{P1V1}{T1}$ = $\frac{P2V2}{T2}$

$V_{2}$ = $\frac{P1V1}{T1}$ $\times$ $\frac{T2}{P2}$

= $\frac{1.5\times3.0\times303}{293\times5.2}$

$\approx$ 1.0L

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4 years ago

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Answer:

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4 years ago

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Answer:

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3 years ago

Read 2 more answers

Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.

MatroZZZ [7]

<span>Mass of the solution = 0.17m
Kb for C6H5NH2 = 3.8 x 10^-10
We know Ka for C6H5NH2 = 1.78x10^-11
We have Kw = Ka x Kb => Ka = Kw / Kb
=> (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
K^2 = 3 x 10^-12 => K = 1.73 x 10^-6.
pH = -log(Kw(H3O^+)) = -log(1.73 x 10^-6) = 5.76</span>

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3 years ago