The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that
there is enough of each compound to contain 2 g of X. In XY the mass of X is 2 g and the mass of Y is 4 g.
Arrange the following ratios in order of their increasing value. Rank from highest to lowest ratio. To rank items as equivalent, overlap them.
1. The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY.
2. The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY.
3. The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY.
Arrange the following ratios in order of their increasing value. Rank from highest to lowest ratio. To rank items as equivalent, overlap them.
1. The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY.
2. The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY.
3. The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY.
1 answer:
Answer:
Ratios in order of increasing value ; The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY
1) Mass ratio = 3
2) Mass ratio = 2
3) Mass ratio = 4
Explanation:
The detailed and step by step calculation is shown in the attachment.
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Answer:
Measuring with a ruler and using final volume minus initial volume
Explanation:
You can measure the volume of a geometric object by measuring its sides with a ruler and calculating the volume according to the corresponding formula for each object. For example, for a rectangular prism it would be
You can also measure the volume of an object by measuring how much water it displaces. To do this you have to fill a measuring cylinder with enough water for the object to be completely submerged and take note of the volume. Then, add the object and note again the volume of the water+object. The difference between both is the volume of the object.
The advantage of the second method is that it can be used for objects with irregular shapes as long as they do not float.