Answer:
A = 82.53 in²
Step-by-step explanation:
We use the circumference equation C = 2πr and the area equation A = πr².
Using the first equation and the given circumference (32 in), we find the radius of the circle, and then use this result to find the area of the circle.
C 32 in
C = 2πr becomes r = ----------- and here r = ---------- = 5.10 in
2π 6.28
Then the area of the circle is A = πr², which here is A = 3.14(5.10 in)², which, when rounded off to two decimal places, is A = 82.53 in²
Answer:
6n-2 = 22
Step-by-step explanation:
n = 4
6(4)-2
24-2
22
Answer:
y=
Step-by-step explanation:
Perpendicular lines have negative reciprocal gradients(slopes) so the slope of your new line would be 1/2. Then you use the point to find the new y-intercept
y=mx+b
2=
(8)+b
2=4+b
B=-2
y=
Answer:
g(x) is shifted 6 units to the left
Step-by-step explanation:
Lets try to simplify g(x) since has a few extra terms:
g(x)= 3x+12-6=3x+6
Now it is easier to compare the two functions.
We can tell that they both have the same slope, both differs on a extra term
This term tell us that the g(x) is shifted to the left (it is positive 6)
Another approach to the solution is to plot the two functions together by obtaining the crossing points with the 'y' axis and with the 'x' axis
the result is shown in the attached picture
Using z-scores, it is found that the value of z is z = 1.96.
-----------------------------
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula, which for a measure X, in a distribution with mean
and standard deviation
, is given by:
- It measures how many standard deviations the measure is from the mean.
- Each z-score has an associated p-value, which is the percentile.
- The normal distribution is symmetric, which means that the middle 95% is between the <u>2.5th percentile and the 97.5th percentile</u>.
- The 2.5th percentile is Z with a p-value of 0.025, thus Z = -1.96.
- The 97.5th percentile is Z with a p-value of 0.975, thus Z = 1.96.
- Thus, the value of Z is 1.96.
A similar problem is given at brainly.com/question/16965597