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3 years ago

Does it lie inside, outside, or on the circle?

Mathematics

1 answer:

FrozenT [24]3 years ago

8 0

Answer:

Given circle:

(x - 4)² + y² = 25

The center is at (4, 0) and the radius is 5 units

Lets find the distance from (7, 2) to the center of the circle:

$d = \sqrt{(7 - 4)^2 + (2 - 0)^2} = \sqrt{9+4} = \sqrt{13} < 5$

Since d < 5, the point (7, 2) lies inside the circle

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Solve the equation for <img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-fo

riadik2000 [5.3K]

X = 35

Step 1: Multiply both sides of the equation by seven thirds

Step 2: Reduce sides

Step 3: Multiply the numbers

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3 years ago

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Point V lies between points U and W on Line segment U W.

Nutka1998 [239]

Answer:

The correct answer is (d) 36 units.

Step-by-step explanation:

Just took the test on edge :)

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3 years ago

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parallelogram ABCD has vertices A(-2,-51/2), B(-4,-51/2), C(-3,-2), and D(-1,-2). find the vertices of parallelogram A'B'C'D' af

Volgvan

On a coordinate plane, any movement up and down is on the y-axis. So if your parallelogram is moving down 2.5 units, then the y-values of each vertice will go down by 2.5:
A(-2, -8), B(-4, -8), C(-3, -4.5), D(-1, -4.5)

7 0

3 years ago

Y=2/x-3 make x the subject

svp [43]

Multiply both sides by x - 3 to get :

y(x - 3) = 2

yx - 3y = 2

yx = 2 + 3y

x = (2 + 3y)/y

Hope this helps! Any questions let me know :)

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3 years ago

20 POINTS!!! PLZ ANSWER!! On the moon, the time, in seconds, it takes for an object to fall a distance, d, in feet, is given by

scoundrel [369]

Answer:

Part a) $f(2)=1.57\ sec$

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) see the explanation

Part c) $2,165.43\ sec$

Step-by-step explanation:

Let

f(d) -----> the time in seconds it takes for an object to fall

d -----> distance in feet

we have

$f(d)=1.11\sqrt{d}$

Part a): Determine f(2) and explain what it represents

we know that

f(2) represent the time in seconds it takes for an object to fall a distance of 2 feet

For $d=2\ ft$

substitute in the function above and solve for f(2)

$f(2)=1.11\sqrt{2}$

$f(2)=1.57\ sec$

therefore

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}

What does this tell you about the basin?

The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft

The maximum height of the basin is 3,805,774 ft

Part c) How long would it take a rock to drop from the rim to the bottom of the basin?

we know that

The distance from the rim to the bottom of the basin is equal to the maximum height of the basin

$d=3,805,774\ ft$

substitute the value of d in the function f(d)

$f(d)=1.11\sqrt{3,805,774}$

$f(d)=2,165.43\ sec$

3 0

3 years ago

Does it lie inside, outside, or on the circle?​

Does it lie inside, outside, or on the circle?