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Vika [28.1K]
3 years ago
11

Classify this triangle by its sides?

Mathematics
2 answers:
antoniya [11.8K]3 years ago
8 0
First option, scalene
bazaltina [42]3 years ago
4 0

Answer:

Scalene

Step-by-step explanation:

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5 yd<br> 3 yd<br> 4.8 yd<br> 28 yd<br> 8 yd
kompoz [17]

Answer:

i am converting to meters

Step-by-step explanation:

5 yd =4.572 meters

3yd=2.7432 meters

4.8yd=2.7432 meters

28yd=25.6032 meters

8yd=7.3152 meters

5 0
3 years ago
Graph the line that has slope 1/2 and y intercept (0,-1).
puteri [66]

Answer: I added an attachment of what the graph should look like! :)

Step-by-step explanation:

5 0
2 years ago
The ratio of the perimeters of two rectangles is 4 to 7. The perimeter of the larger rectangle is 42 inches. What is the perimet
drek231 [11]
In the given situation, the ratio of the perimeters of two rectangles is 4 to 7. The perimeter of the larger rectangle is 42 inches.Now, let's find the perimeter of the smaller.Let's solve for the answerRatio and formula:=> 4 : 7 = X = 42, where x is the unknown perimeter of the smaller rectangle=> 4 * 42 = 168 / 7 = 24Thus the answer is letter D. 24 inches is the parameter of smaller rectangle.<span>
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4 0
3 years ago
A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria
Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

9000 = 400e^{k4}.

Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

6 0
3 years ago
What is the power to another power rule
Sholpan [36]

Answer:

9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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