The solution of the inequality is x ≥ 1.
Solution:
Given inequality:

To find the solution of the inequality:

Subtract 8 from both sides.


Divide by 3 on both sides.

On simplifying this, we get

The solution of the inequality is x ≥ 1.
The graph of the solution is attached below.
Answer: $11836.8
Step-by-step explanation:
Given. That :
Amount invested = $5000
Interest rate = 9% = 0.09
Period = 10 years, compounded annually
Using the compound interest formula :
A = p(1 + r/n)^nt
A = final amount
P = principal or invested amount
r = rate of interest
n = number of times interest Is applied per period
t = period
A = 5000(1 + 0.09/1)^(1*10)
A = 5000(1.09)^10
A = 5000 * 2.36736367459211723401
A = 11836.81837296058617005
= $11836.8
Verify please dont understand
The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.
1.

We want to find
such that
. This means



so
is conservative.
2.

Then




so
is conservative.
3.

so
is not conservative.
4.

Then




so
is conservative.
Answer:
- 3/8 in/ft
- 1/32 . . . (pure number, no units)
Step-by-step explanation:
The ratio can be expressed directly as ...
... (6 in)/(16 ft) = 3/8 in/ft
This can be read or used in different ways:
Or, the units can be made compatible and the ratio expressed as a pure number.
... (1/2 ft)/(16 ft) = (1/32) ft/ft = 1/32
This means whatever measurement is made on the model, the actual vehicle measurement is 32 times that.