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3 years ago

8

5/2c-3=3/7c+4 and please explain

1 answer:

Naddika [18.5K]3 years ago

5 0

5/2c - 3 = 3/7c + 4...subtract 3/7c from both sides
5/2c - 3/7c - 3 = 4.....add 3 to both sides
5/2c - 3/7c = 4 + 3....common denominator of 7 and 2 is 14
35/14c - 6/14c = 7...simplify
29/14c = 7....multiply both sides by 14/29, eliminating the 29/14 on left
c = 7 * 14/29
c = 98/29 = 3 11/29

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$\boxed{\sf x=-2}$

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Step-by-step explanation:

<u>First, Let's solve for x in -2x+2y=-4:</u>

$\sf -2x+2y=-4$

<u>Subtract 2y from both sides:</u>

$\sf -2x+2y-2y=-4-2y$

$\sf -2x=-4-2y$

<u>Divide both sides by -2:</u>

$\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}$

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<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

$\sf 3x+3y=-18$

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$\sf 3\bold{(2+y)}+3y=-18$

<u>Simplify:</u>

$\sf 6+6y=-18$

<u>Now, let's solve for y in 6+6y=-18</u>

$\sf 6+6y=-18$

<u>Subtract 6 from both sides:</u>

$\sf 6+6y-6=-18-6$

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<u>Divide both sides by 6:</u>

$\sf \cfrac{6y}{6}=\cfrac{-24}{6}$

$\bold{ y=-4}$

<u>Now, substitute y=-4 into x=2+y:</u>

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Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

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