Answer:
Lily is correct.
An example of a working solution to this problem is: 6/3 + 1/2 + 4/8.
Step-by-step explanation:
An integer is essentially a whole number(is not a part), but with negative numbers as well. Given whole numbers from 1 to 9, This can be an integer because an integer <u>includes</u> whole numbers.
Answer:
Subtracting 7
Step-by-step explanation:
<u><em>Given:</em></u>
<em>Clara is stacking cups; she put 45 plastic cups in the first stack, 38 plastic cups in the second stack, 31 plastic cups in the third stack, and 24 plastic cups in the fourth stack. </em>
<u><em>To Find:</em></u>
<em>What kind of sequence is this?</em>
<u><em>Solve:</em></u>
<em>Let's make a table:</em>
<em />
<em>[1 stack] 45 </em>
<em>[2 stack] 38</em>
<em>[3 stack] 31</em>
<em>[4 stack] 24</em>
<em />
<em>Now all we have to do is subtract to see what each is:</em>
<em>45 - 38 = 7</em>
<em>38 - 31 = 7</em>
<em>31 - 24 = 7</em>
<em>Thus,</em>
<em>[1 stack] 45 ⇒ 7</em>
<em>[2 stack] 38 ⇒ 7 </em>
<em>[3 stack] 31 ⇒ 7 </em>
<em>[4 stack] 24 ⇒ 7 </em>
<em>Hence, each stack is going down by 7.</em>
<em />
<u><em>Kavinsky</em></u>
<em />
Answer:
The amount of Kroner that can be bought from 1/5 of one dollar.
Step-by-step explanation:
We have been given that goods that cost 1/5 of one dollar in the U.S. cost one kroner in Denmark. We are asked to find the the real exchange rate that would be computed as how many Danish goods per U.S. goods.
The real exchange rate tells us how much foreign currency can be exchanged for a unit of domestic currency.
It also tells us that how much the goods and services in the domestic country can be exchanged for the goods and services in a foreign country.
Therefore, the real exchange rate would be the amount of Kroner that can be bought from 1/5 of one dollar.
Answer: p(x) = a (x-b)(x-c)(x-d)
Step-by-step explanation:
The first step is to determine the degree of the polynomial.
It shall depend totally on the linear factors given for the polynomial.
If there is one, it is a linear polynomial.
If there are 2, then it is a quadratic polynomial.
If there are three then it shall be a cubic polynomial.
Now let us assume that there are three linear factors.
We multiply those factors and write the polynomial.
If x-b, x-c & x-d are the factors we write
p(x) = (x-b)(x-c)(x-d)
But as we may have a leading coefficient so we write the polynomial as
Then we go on to expand this to get the polynomial in the standard form.
The characteristic solution follows from solving the characteristic equation,

so that

A guess for the particular solution may be

, but this is already contained within the characteristic solution. We require a set of linearly independent solutions, so we can look to

which has second derivative

Substituting into the ODE, you have



Therefore the particular solution is

Note that you could have made a more precise guess of

but, of course, any solution of the form

is already accounted for within

.