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borishaifa [10]
2 years ago
15

It's actually 3 questions, please help me with what you can.

Mathematics
1 answer:
Mila [183]2 years ago
3 0

Answer:

1.✓3/2

2 2✓6/5

3cosecθ

have a great day ahead

please mark me as the brainliest

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Michael is a real estate agent who sells a house. He received $5,250 for a 3% commission on the house. How much did the house se
Alborosie

Answer: $157.50

Step-by-step explanation:

$5250÷100=$52.50

52.50×3=$157.50

7 0
2 years ago
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max's stamp collection has stamps for different countries.he has 12 stamps from canada.of those tweleve,2/3 of them have picture
solong [7]
8 stamps. Multiply 2/3 by 12 and you have your answer
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3 years ago
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The weights of cars passing over a bridge have a mean of 3,550 pounds and
Dovator [93]

The approximate probability that the weight of a randomly-selected car passing over the bridge is more than 4,000 pounds is 69%

Option C is the correct answer.

<h3>What is Probability ?</h3>

Probability is defined as the study of likeliness of an event to happen.

It has a range of 0 to 1.

It is given in the question that

The weights of cars passing over a bridge have a mean of 3,550 pounds and standard deviation of 870 pounds.

mean  = 3550

standard deviation,  = 870

Observed value, X = 4000

Z = (X-mean)/standard deviation = (4000-3550)/870 = 0.517

Probability of weight above 4000 lb

= P(X>4000) = P(z>Z) = P(z> 0.517) = 0.6985

The approximate probability that the weight of a randomly-selected car passing over the bridge is more than 4,000 pounds is 69%

To know more about Probability

brainly.com/question/11234923

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6 0
2 years ago
The coordinate plane below represents a city. Points A through F are schools in the city.
Usimov [2.4K]
Part A. The technique on how to find the equation that only applies to point D and E, is to create a line or curve that only includes two of these points. In this case, I created a random parabola that isolates points C and F from the rest of the points. First, we have to find the equation of the parabola through its general forms:

(x - h)² = +/-4a(y-k)      or    (y - k)² = +/-4a(x - h)

For parabolas drawn like that in the picture, the general form is (x - h)² = +4a(y-k), where the vertex is (h,k) and a is the distance from the vertex to the focus. From the picture, the vertex is at (0,3). Then, we use point D(-2,4) to determine a:

(-2 - 0)² = +4a(4 - 3)
4a = 4

So, the equation of the parabola is:

x² = 4(y - 3)
x² = 4y - 12

Part B. Point D was already verified above. Now for point E(2,4)
x² = 4y - 12
2² ? 4(4) - 12
4 ? 4
4 = 4

Part C. For y < 7x − 4, ignore the equality symbol first and graph the line. Assign random values of x, then you get corresponding values of y. Plot them as shown in the second picture. The line is shown in red. Next, test the equation by choosing a random point. Let's choose the purple point at (4,3).

3 ? 7(4) − 4
3 ? 24
3 < 24

Thus, it applies to the purple point, and all the other areas to that area. The shaded region are all solutions of the inequality. So, Erica is only interested in points E, C and F. 

5 0
3 years ago
Mrs. Portillo's cat weighs 6 kilograms. Her dog weighs 22 kilograms more than her cat. What is the total weight of her cat and d
topjm [15]
Cat=6
dog=22+6
total kilograms = 6+(22+6)= 34
5 0
3 years ago
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