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erma4kov [3.2K]
3 years ago
7

What is 15/9 as a percent

Mathematics
1 answer:
Verizon [17]3 years ago
5 0

Answer: 16.7%

Step-by-step explanation:

15/9=1.67 1.67x100=167 so 16.7%=0.0167

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Y=1/3 x-4 system of equations
anyanavicka [17]

Answer:

What are you asking?

Step-by-step explanation:

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3 years ago
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An experiment was conducted by some students to explore the nature of the relationship between a person's heart rate (measured i
tekilochka [14]

Answer:

A. factors.

Step-by-step explanation:

The correct option is - A. factors.

Reason -

The variables "stepping rate" and "step height" are the factors because a activity is performed in which stepping at one of the three stepping rates at one of the two possible heights for three minutes.

The activity is based on both the variables stepping rate and step height.

6 0
3 years ago
The sum of five and three times a number is 74. Find the number.
Helga [31]

Answer:23

Step-by-step explanation:

7 0
4 years ago
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Use substitution. <br> 2x +3y = -5<br> 4x+3y= 17
Goshia [24]

Answer:

Step-by-step explanation:

-2x -3y = 5

4x + 3y = 17

2x = 22

x = 11

4(2) + 3y = 17

8 + 3y = 17

3y = 9

y = 3

(11,3)

3 0
3 years ago
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Determine what type of model bet fits the given situation: Every day, half a bacteria population dies. A. Linear B.quadratic C.
makvit [3.9K]

Answer:

Exponential

Step-by-step explanation:

<em>Starter:</em>

According to the title:

"Every day, half a bacteria population dies."

Exponential: y = ab^x ( b > 0 , b ≠ 1)

So the answer is C.

<em>Calculations:</em>

An exponential model is of the form y = a • b^t.

If you start with population of 500 million bacteria

t = 0

so 500 million = a • b^0 = a

Since every day half the population dies then in 1 day population will be 250 million

so a = 500 million, y = 250 million and t = 1

250 million = 500 million • b^1

b = 0.5

Therefore your equation would be

y = 500 million (or whatever the pop) • 0.5^t

Where t = number of days

This could also be written in exponential form ( e = 2.73)

4 0
2 years ago
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