Yes, both have the 110 degrees angle, and according to some theorem, the interior angles formed by the intersection of the 2 lines, they are also congruent angles (the y angles). All that remains is the x angle, which is congruent to the other angle.
The geometrical relationships between the straight lines ab and cd
is the straight line ab is parallel to the straight line cd
Step-by-step explanation:
Let us revise some notes:
- If a line is drawn from the origin and passes through point A (a , b), then the equation of OA = ax + by
- If a line is drawn from the origin and passes through point B (c , d), then the equation of OB = cx + dy
- To find the equation of AB subtract OB from OA, then AB = (c - a)x + (d - b)y
- The slope of line AB =

∵ oa = 2 x + 9 y
∵ ob = 4 x + 8 y
∵ ab = OB - OA
∴ ab = (4 x + 8 y) - (2 x + 9 y)
∴ ab = 4 x + 8 y - 2 x - 9 y
- Add like terms
∴ ab = (4 x - 2 x) + (8 y - 9 y)
∴ ab = 2 x + -y
∴ ab = 2 x - y
∵ The slope of ab = 
∵ Coefficient of x = 2
∵ Coefficient of y = -1
∴ The slope of ab = 
∵ cd = 4 x - 2 y
∵ Coefficient of x = 4
∵ Coefficient of y = -2
∴ The slope of cd = 
∵ Parallel lines have same slopes
∵ Slope of ab = slope of cd
∴ ab // cd
The geometrical relationships between the straight lines ab and cd
is the straight line ab is parallel to the straight line cd
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Answer:
I believe the answer is D.
Step-by-step explanation:
The Answer makes sense.
To find the height that the rocket has reached, we can use the following equation to calculate distance.
s = ut + 1/2 at²
s - distance - h
u - initial velocity - 64 ft/s x 0.3048 m/ft = 19.5 m/s
a - acceleration, since the rocket is travelling upwards against gravitational acceleration, its said to be deceleration. therefore value is -9.8 ms⁻²
t - time taken - t seconds
substituting values in the equation
h = 19.5 ms⁻¹ x t s - 1/2 x 9.8 ms⁻² x (t s)²
h = 19.5t - 4.9t²
Answer:
Population after 
Step-by-step explanation:
If
is the initial amount,
is the annual rate of decrease then after
years the remaining amount
will be given by

Here 