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melisa1 [442]
4 years ago
15

Question 11 point(s) Jared made Ask Your Teacher cups of snack mix for a party. His guests ate Ask Your Teacher of the mix. How

much snack mix did his guests eat?
Mathematics
1 answer:
liq [111]4 years ago
5 0

Answer:

8\frac{1}{2} cups

Step-by-step explanation:

To determine the quantity of snack mix Jared guest ate, we multiply the quantity of snack mix the guest ate by the quantity of snack mix Jared made. i.e we determine \frac{2}{3}of12\frac{3}{4} by multiplying both fractions together

quantity of snack mix Jared guest ate = \frac{2}{3}of12\frac{3}{4}=\frac{2}{3}*12\frac{3}{4}=\frac{2}{3}*\frac{51}{4}=\frac{17}{2} =8\frac{1}{2}

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One third as a decimal
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The first term in a geometric sequence is 54, and the 5th term is 2 / 3. Find an explicit form for the geometric sequence.
quester [9]

Answer:  ar^{n-1}=54(\dfrac{1}{3})^{n-1}

Step-by-step explanation:

The nth term for a geometric sequence is given by :-

a_n=ar^{n-1}    (1)

We are given that The first term in a geometric sequence is 54. i.e. a=54

5th term=\dfrac{2}{3}   (2)

Put n=5 and a= 54 in (1), we get

a_5=(54)r^{4}=     (3)

From (2) and (3), we have

\Rightarrow(54)r^{4}=\dfrac{2}{3}\\\\\Rightarrow r^4=\dfrac{2}{3}\times\dfrac{1}{54}=\dfrac{1}{3\times27}=\dfrac{1}{81}\\\\\Rightarrow\ r=(\dfrac{1}{81})^{\frac{1}{4}}=\dfrac{1}{3}

Explicit form for the geometric sequence: ar^{n-1}=54(\dfrac{1}{3})^{n-1}

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4 years ago
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