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3 years ago

15

Question 11 point(s) Jared made Ask Your Teacher cups of snack mix for a party. His guests ate Ask Your Teacher of the mix. How

much snack mix did his guests eat?

1 answer:

liq [111]3 years ago

5 0

Answer:

$8\frac{1}{2}$ cups

Step-by-step explanation:

To determine the quantity of snack mix Jared guest ate, we multiply the quantity of snack mix the guest ate by the quantity of snack mix Jared made. i.e we determine $\frac{2}{3}of12\frac{3}{4}$ by multiplying both fractions together

quantity of snack mix Jared guest ate = $\frac{2}{3}of12\frac{3}{4}=\frac{2}{3}*12\frac{3}{4}=\frac{2}{3}*\frac{51}{4}=\frac{17}{2} =8\frac{1}{2}$

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The area of a parallelogram is 96 cm squared the height is 4 cm less than the length what is

andrey2020 [161]

Area of paralellogram=legnth times height

l=legnth
h=height
area=96

lh=96

h is 4 less than l
h=-4+l
sub
l(-4+l)=96
-4l+l^2=96
minus 96 both sides
l^2-4l-96=0
factor
(l-12)(x+8)=0
set to zero
l-12=0
l=12

l+8=0
l=-8, imossible, legnth cannot be negative, disreagard this soultion

legnth=12cm

8 0

3 years ago

Read 2 more answers

Circle J and circle K are shown in the diagram below.

vagabundo [1.1K]

Check the picture. There are 2 interior common tangents, and 2 exterior common tangents which can be drawn.

Answer: 4

5 0

3 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

3 years ago

write the equation of the line that is parallel to y = 4x -7 and passes through the point (-2, -5). show your work.

natita [175]

Answer:

y = 4x + 3

Step-by-step explanation:

To do this, put the new line into the form y = mx + b where m is the slope and b is the y-intercept.

When two lines are parallel, they have the same slope. Since, the slope of the first line is 4, that means the slope of the second line is also 4.

So far, the equation is y = 4x + b.

Then, since you know (-2, -5) is a solution, x = -2, y = -5 is a solution so you can plug this into the equation.

This would be:

-5 = 4 * -2 + b

-5 = -8 + b

3 = b

This means the equation is y = 4x + 3.

7 0

3 years ago

I need to find x & y. plz answer i really need thisssss. only if correct :)

Leto [7]

Answer:

x=12, y= 20

Step-by-step explanation:

We can find x using the pythagorean thereom because ABD is a right triangle.(D is the point between segments with legnth 5 and 11)

AC^2 + CD^2 = AD^2

x^2 + 5^2 = 13^2

x^2 = 25 = 169

x^2 = 144

x = 12

We may now find y using the pythagorean thereom because ABC is a right triangle. Right now we know x = 12

AC^2 + CB ^2 = AB^2

12^2 + 16^2 = y^2

144 + 256 = y^2

y^2 = 400

y= 20

<em>I hope this helps! :)</em>

5 0

3 years ago