Answer:
12s - 16t
Step-by-step explanation:
2(3s + t) + 2(3s - 9t)
6s + 2t + 6s - 18t
12s + 2t - 18t
12s - 16t
Answer:
Answer is 3
Step-by-step explanation:
x/3-2x/1+3 =x-3/5
x/3-x/3 = x-3/5
0=x-3/5
0=x-3
3=x
sothat, x = 3 ans
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.