Answer:
145
Step-by-step explanation:
y=kx
87=3k
k= 87/3
k= 29
y=29×5
y= 145
Answer:

Step-by-step explanation:
The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

We first compute the n-th derivative of
, note that

Now, if we compute the n-th derivative at 0 we get

and so the Maclaurin series for f(x)=ln(1+2x) is given by

B. if two lines are perpendicular, then they intersect to form four right angles.
Step-by-step explanation:
y > -15
y is bigger than -15
= -14 , -13 , -12 , -11 , -10 , etc . . .