Population: six sugar maples
Sample: sap
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
3 to the negative second power is written like this:

.
When simplifying an expression with a negative exponent, you take a positive version of the exponent, in this case that would be 2, and apply that to the base.
After doing that, we have 9.
The next step is to put one over that number.
In this case, now after doing that the answer is

.
Hope this helps!
Answer:
Step-by-step explanation:
2√54+5√24
2 * sqrt(9*6) + 5*sqrt(4*6)
2*sqrt(9) *sqrt(6) + 5*sqrt(4) * sqrt(6)
2*3 sqrt(6) + 5*2 sqrt(6)
6sqrt(6)+10sqrt(6)
16sqrt(6)