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mojhsa [17]
3 years ago
14

A car travels at a steady speed. It covers 60km in 40 minutes. How far will it travel in 3 hours, assuming it continues at the s

ame rate?
Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

Answer:

270km

Step-by-step explanation:

3 hours is 180 minutes

40 minutes - 60km

180 minutes - x km

x = 180/40 * 60 = 270km (the speed is 90km/h)

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Pleaaseee help, i need the answer asap! (WILL GIVE BRAINLIEST!!)
Setler79 [48]

Answer:

A.

Step-by-step explanation:

Substituting the ordered pairs into the equation. 3x - y/4 = 11

For (3,-8)

3 * 3 - (-8)/4

9- (-2) = 11

For (4, 4)

3 * 4 - 4/4

12 - 1 = 11

Both ordered pairs equals to 11, therefore, they're both solutions to the equation.

8 0
3 years ago
Write an expression using all six trigonometric functions such that the value of the expression is 3.
iren2701 [21]
The trig functions that you need to deal with are
Sine
Cosine
Tangent
Cotangent
Cosecant
Secant

You need to write a single expression using all six trig functions such that the value of the expression equals 3.

To make this as simple as possible, the first thing I would do is look up the values of these functions and identify which ones are equal to either 1/2 or 1.0 or 2.0

sin(30º) = 1/2
sin(90º) = 1
cos(0º) = 1
cos(60º) = 1/2
tan(45º) = 1
csc(30º) = 2
csc(90º) = 1
sec(0º) = 1
sec(60º) = 2
cot(45º) = 1

If we only had to use three trig functions (sin, cos, tan), one possibility is
tan(45º) + cos(0º)/sin(30º) = 1 + 1/(1/2) = 1 + 2 = 3
noticed how I chose one each of the required functions and the operations so that the result = 3.

Now it is up to you to figure out how to combine all six trig functions so that they equal zero. There are many possibilities for you to choose from..
6 0
3 years ago
A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan
seropon [69]

Answer:

32 unit^{3}

Step-by-step explanation:

Given:

  • The slant length 10 units
  • A right square pyramid with base edges of length 8\sqrt{2}

Now we use  Pythagoras to get the slant height in the middle of each triangle:

\sqrt{10^{2 - (4\sqrt{2} ^{2} }) } = \sqrt{100 - 32} = \sqrt{68}  units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

\sqrt{68-(4\sqrt{2} ^{2} )} = \sqrt{68 - 32} = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

  • The height 3 units
  • A right square pyramid with base edges of length 4\sqrt{2}

So the volume of it is:

V  = 1/3 *3* 4\sqrt{2}

= 32 unit^{3}

5 0
4 years ago
Can you wear slip on shoes without socks
Naddika [18.5K]
It'd be a crime not to
8 0
3 years ago
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